Question

我想在List Comprehensions上插入一个插件。我能做到？

t = ['test','tes']
x = ['1','2','3','4','5']
t.insert([0,i]for i in x)

Answer 1

如果你要找的结果是这样的

define(['plugins/router', 'durandal/app', 'gcharts', 'jquery'], function (router, app, gcharts, $) {

    var projectStatsModel = function (data) {

        this.projectId = data.projectId;
        this.projectName = data.projectName;
        this.projectDescription = data.projectDescription;
        this.projectPlatform = data.projectPlatform;

        this.projectPointsLabel = "Total Points: " + data.projectNumPoints;
        this.projectStoriesLabel = "Total Stories: " + data.projectNumStories;
        this.projectCreatedDateLabel = "Created " + data.projectCreationDate;
        this.projectUpdateDateLabel = "Last Updated " + data.projectModifyDate;

        this.projectEpics = data.projectEpics;
        this.projectStories = data.projectStories;

        return this;
    }

    var ctor = function () {

        function drawPage(data) {
            var model = projectStatsModel(data);
            ko.applyBindings(model);
        }

        function loadData() {

            var projectId = router.activeInstruction().params[0];

            $.ajax({
                url: '/ClubhouseData/GetProjectDetails',
                data: {
                    'projectId': projectId
                },
                type: 'GET',
                cache: 'false',
                success: function (result) {
                    console.log(result);
                    drawPage(result);
                }
            });
        }

        ctor.prototype.activate = function () {
            loadData();
        }
    };


    return ctor;
});

代码如下：

['test', 'tes', [0, 'test'], [0, 'tes']]

Answer 2

你可以在列表理解中完成它但最终会做额外的工作。只需在for循环中执行：

for thing in x:
    t.insert(0, thing)

Answer 3

t = ['test','tes']
x = ['1','2','3','4','5']
out = t + x

你的输出将是['tes'，'test'，'1'，'2'，'3'，'4'，'5'，'6'] 或者那些单独的东西。 python允许你连接字符串

Answer 4

ListItemLabel只接受字符串。我想在列表中给它多个元素，我在ListItemLabel前面str中使用它，但是它没有做任何事情。

我不知道你的思维方式是否正确

的Python：

result_true = ListProperty([])

extra = self.viewedit.adapter.data 

for edit in extra: 
   if edit['active'] == True:

    app.result_true.append(edit['text'])
    #app.result_true = (edit['text'])
    print app.result_true

Kivy：

ListItemLabel:
text:str(ctx.edit)

返回：

[＆＃39; \ XCE \ XBB \ XCE \ xb9 \ XCE \ XB1 \ XCF \ X83 \ XCF \ X84 \ XCE \ XAE \ XCE \ XBD \ XCF \ X84 \ XCE \ XBF \ XCE \ XBC \ XCE \ XAC \ XCF \ X84 \ XCE \ XB1＆＃39 ;, ＆＃39; \ XCF \ X83 \ XCE \ XBF \ XCF \ X85 \ XCF \ X83 \ XCE \ XAC \ XCE \ XBC \ XCE \ xb9＆＃39 ;, ＆＃39; \ XCF \ X84 \ XCF \ X85 \ XCF \ X81 \ XCE \ XAF＆＃39;]

我可以用List Comprehensions插入我的列表吗？

4 个答案: