Question

我有一个增量变量，我想将它存储到堆栈或数组中进行打印。

我的代码就像：

private Calendar schedule;

public void addScheduleNotificationFireEvent(List<Integer> scheduleList, long timeFromMeetingInSeconds){
    schedule = Calendar.getInstance();
    Log.d(DEBUG_TAG,"After Instance: " + schedule.getTimeInMillis());
    long currentMillis = System.currentTimeMillis();
    schedule.setTimeInMillis(currentMillis);
    Log.d(DEBUG_TAG,"After setMillis: " + schedule.getTimeInMillis());
    schedule.set(scheduleList.get(0),scheduleList.get(1),scheduleList.get(2),scheduleList.get(3),scheduleList.get(4),0);
    Date scheduleTime = schedule.getTime();
    long testCase = (((scheduleTime.getTime() - NOTIFICATION_FIRE_OFFEST_TIME - timeFromMeetingInSeconds*1000)-currentMillis)/1000);
    Log.d(DEBUG_TAG,"TestCase Value: " + Long.toString(testCase));
    Log.d(DEBUG_TAG,"schedtime: " + scheduleTime.getTime());
    Log.d(DEBUG_TAG,"NOTIF_OFF: " + NOTIFICATION_FIRE_OFFEST_TIME);
    Log.d(DEBUG_TAG, "TIME_MEETING: " + timeFromMeetingInSeconds*1000);
    Log.d(DEBUG_TAG,"Current millis: " + currentMillis);
    if(testCase > 0) {
        Intent scheduleStepOutIntent = new Intent(mContext, MeetAppNotifierService.class)
                .setAction("com.cyberfox.meetapp.SHOW_SCHEDULED_STEP_OUT_NOTIFICATION");
        PendingIntent pi = PendingIntent.getService(mContext,0,scheduleStepOutIntent,PendingIntent.FLAG_ONE_SHOT);
        AlarmManager alarmManager = (AlarmManager)mContext.getSystemService(Context.ALARM_SERVICE);
        alarmManager.setExact(AlarmManager.RTC_WAKEUP,(scheduleTime.getTime()-NOTIFICATION_FIRE_OFFEST_TIME-timeFromMeetingInSeconds*1000),pi);
        Log.d(DEBUG_TAG,"triggering at: " + testCase);
    }
    else{
        Intent scheduleNotPossible = new Intent("MY_INTENT_HERE");
        mContext.sendBroadcast(scheduleNotPossible);
    }
    schedule.clear();
    schedule = null;
    scheduleTime = null;
}

在这种情况下，正在发生的是打印计数器，但它是单独打印的。我希望我的输出结合如下。因此，我希望所有计数器值都存储在数组或堆栈中。

{
    int counter = 0;
    for(int i = 0; i < p; i++){
        for (int j = 0; j < n; j++){
        if (stringVal[p].equals(stringVal2[j])) 
            counter++;                                           
        }
        System.out.println(counter);
    }
}

有人可以帮我解决这个问题吗？

Answer 1

不是将所有计数器值存储在堆栈或数组中，而是可以在if条件下编写打印代码，如：

    {
        int counter = 0;
        for(int i = 0; i < p; i++){
        for (int j = 0; j < n; j++){
        if (stringVal[p].equals(stringVal2[j])) 
            System.out.println(counter++);                                           
        }

    }
}

上述方法可以节省时间和内存。

如何将增量变量存储到数组或堆栈中

1 个答案: