ShipmentRouteInfo 表
ShipmentID OriginSite Stop1 Stop2 DestinationSite Quantity
----------------------------------------------------------------------------------
1 A B C D 10 //Taking all stops
2 E B NULL F 20 //Shipment goes from E to F via B
3 G NULL NULL H 30 //Shipment goes from G to H, no stops taken
我希望将此表转换为。
ShipmentID OriginStopDestination Site PathID Quantity
----------------------------------------------------------------------------------
1 Origin A A_D 10
1 Stop1 B A_D 10
1 Stop2 C A_D 10
1 Destination D A_D 10
2 Origin E E_F 20
2 Stop1 B E_F 20
2 Destination F E_F 20
3 Origin G G_H 30
3 Destination H G_H 30
我希望为此格式Path ID的每件货件生成OriginSite_DestinationSite，并为每个来源网站stop1，stop2，目标网站生成一个单独的行。
这是我到目前为止所做的。
SELECT TOP 100 PERCENT Z.ShipmentID, Z.OriginStopDestination, Z.Site, Z.PathID, Z.Quantity
FROM (
SELECT A.ShipmentID, 'Origin' as OriginStopDestination, A.OriginSite as Site, CONCAT(CONCAT(A.OriginSite, '_'),A.DestinationSite) as PathID, A.Quantity
FROM ShipmentRouteInfo A
UNION
SELECT B.ShipmentID, 'Destination' as OriginStopDestination, B.DestinationSite as Site, CONCAT(CONCAT(B.OriginSite, '_'),B.DestinationSite) as PathID, B.Quantity
FROM ShipmentRouteInfo B
) AS Z
ORDER BY Z.ShipmentID
给我......
ShipmentID OriginStopDestination Site PathID Quantity
----------------------------------------------------------------------------------
1 Origin A A_D 10
1 Destination D A_D 10
2 Origin E E_F 20
2 Destination F E_F 20
3 Origin G G_H 30
3 Destination H G_H 30
我应该如何修改我的查询以包含停止信息？
请不要从我的查询中删除SELECT TOP 100 PERCENT Z.ShipmentID, Z.OriginStopDestination, Z.Site, Z.PathID, Z.Quantity我需要它用于其他目的。建议我如何修改内部查询块。
答案 0 :(得分：1)
必须有一个问题，因为这对我来说似乎很明显，但你似乎想要的答案是：
SELECT TOP 100 PERCENT Z.ShipmentID, Z.OriginStopDestination, Z.Site, Z.PathID, Z.Quantity
FROM (
SELECT A.ShipmentID, 'Origin' as OriginStopDestination, A.OriginSite as Site, CONCAT(CONCAT(A.OriginSite, '_'),A.DestinationSite) as PathID, A.Quantity
FROM ShipmentRouteInfo A
UNION
SELECT B.ShipmentID, 'Stop1' as OriginStopDestination, B.OriginSite as Site, CONCAT(CONCAT(B.OriginSite, '_'),B.DestinationSite) as PathID, B.Quantity
FROM ShipmentRouteInfo B
WHERE B.Stop1 IS NOT NULL
UNION
SELECT C.ShipmentID, 'Stop2' as OriginStopDestination, C.DestinationSite as Site, CONCAT(CONCAT(C.OriginSite, '_'),C.DestinationSite) as PathID, C.Quantity
FROM ShipmentRouteInfo C
WHERE C.Stop2 IS NOT NULL
UNION
SELECT D.ShipmentID, 'Destination' as OriginStopDestination, D.DestinationSite as Site, CONCAT(CONCAT(D.OriginSite, '_'),D.DestinationSite) as PathID, D.Quantity
FROM ShipmentRouteInfo D
) AS Z
ORDER BY Z.ShipmentID
至少，此查询会继续您开始使用的逻辑，否则会对现有查询进行最少的更改。
答案 1 :(得分：0)
您可以使用UnPivot，如下所示：
Select ShipmentId, originstopdestination, [Site], [Path], Quantity from
(Select *, [Path] = concat(originsite,'-',destinationsite) from #shipments ) a
unpivot ([Site] for [OriginStopDestination] in ([Originsite],[stop1],[stop2], [DestinationSite])) p
输出如下：
+------------+-----------------------+-----------------+------+----------+
| ShipmentId | originstopdestination | Site | Path | Quantity |
+------------+-----------------------+-----------------+------+----------+
| 1 | A | Originsite | A-D | 10 |
| 1 | B | stop1 | A-D | 10 |
| 1 | C | stop2 | A-D | 10 |
| 1 | D | DestinationSite | A-D | 10 |
| 2 | E | Originsite | E-F | 20 |
| 2 | B | stop1 | E-F | 20 |
| 2 | F | DestinationSite | E-F | 20 |
| 3 | G | Originsite | G-H | 30 |
| 3 | H | DestinationSite | G-H | 30 |
+------------+-----------------------+-----------------+------+----------+