Question

我正在尝试根据他们想要保存的列表保存到不同的核心数据对象。

是否可以创建一个传入类型的函数，并根据它保存到正确的列表中？

 let context = (UIApplication.shared.delegate as! AppDelegate).persistentContainer.viewContext
    if index == 0 {
        let task = TodayTask(context: context)

        task.name = taskText.text! // Do this in function insead
        task.adress = addressField.text // Do this in function insead
        task.date = userDate // Do this in function insead

    }else if listIndex.selectedSegmentIndex == 1 {
        let task = WeekTask(context: context)
        task.name = taskText.text!
    }else {
        let task = Task(context: context)
        task.name = taskText.text!

func saveToCoreData(task: SomeList){
    let task = SomeList(context: context) // The correct list based on what the user chooses
    task.name = taskText.text!
    task.adress = addressField.text
    task.date = userDate
}

Answer 1

您应该使用一种称为动态调度的技术。例如：

func accept(value: String) {
    //This to process a string
}

func accept(value: Int){
    //This called to process an Int
}

然后你只需调用accept（value：myValue），该函数将动态调度到正确的函数。

将不同类型传递给函数

1 个答案: