对于大于32位的类型，clang不支持atomic :: is_lock_free吗？

Question

我有以下内容：

struct A { int a[4]; };
struct B { int x, y; };
int main()
{
    std::cout << std::boolalpha
            << "std::atomic<A> is lock free? "
            << std::atomic<A>{}.is_lock_free() << '\n'
            << "std::atomic<B> is lock free? "
            << std::atomic<B>{}.is_lock_free() << '\n';
}

它编译并运行良好，但如果我提高A：

的大小

struct A { int a[5]; };
struct B { int x, y; };
int main()
{
    std::cout << std::boolalpha
            << "std::atomic<A> is lock free? "
            << std::atomic<A>{}.is_lock_free() << '\n'
            << "std::atomic<B> is lock free? "
            << std::atomic<B>{}.is_lock_free() << '\n';
}

好铿锵给出了错误：

Undefined symbols for architecture x86_64:
"___atomic_is_lock_free", referenced from:
    _main in atomics.o
ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)

这是什么错误？是否需要额外的库“is_lock_free”才能使用更大的结构？

问题已解决，请使用“-latomic”链接标记！