我正在开发一个基于书籍信息的网站,我希望在HTML页面的“作者”表中显示所有作者。当我点击链接“authors”时,页面不会呈现,并且会显示错误“用户匹配查询不存在”。 (不要让我在这里发布图片)。 这是来自终端的追溯。
Internal Server Error: /books/authors/
Traceback (most recent call last):
File "C:\Python27\lib\site-packages\django\core\handlers\exception.py", line 41, in inner
response = get_response(request)
File "C:\Python27\lib\site-packages\django\core\handlers\base.py", line 187, in _get_response
response = self.process_exception_by_middleware(e, request)
File "C:\Python27\lib\site-packages\django\core\handlers\base.py", line 185, in _get_response
response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "C:\Users\Pallav\PycharmProjects\onlineBookStore\onlineBookStore\books\views.py", line 35, in follow_user
user_to_be_followed = User.objects.get(username=username)
File "C:\Python27\lib\site-packages\django\db\models\manager.py", line 85, in manager_method
return getattr(self.get_queryset(), name)(*args, **kwargs)
File "C:\Python27\lib\site-packages\django\db\models\query.py", line 380, in get
self.model._meta.object_name
DoesNotExist: User matching query does not exist.
我尝试在python manage.py shell
中运行查询,然后生成一个正确的查询集。
我的urls.py
文件是:
app_name = 'books'
urlpatterns = [
# /books/
url(r'^$', views.IndexView.as_view(), name='index'),
# /register/
url(r'register/$', views.UserFormView.as_view(), name='register'),
# /logout/
url(r'logout/$', views.logout_user, name='logout'),
# /login/
url(r'login/$', views.login_user, name='login'),
# /search/
url(r'search/$', views.search, name='search'),
# /add_book/
url(r'search/(?P<isbn>[0-9]+)/add_book$', views.add_book, name='add_book'),
# /books/<book_id>/
url(r'^(?P<book_id>[0-9]+)/$', views.detail, name='detail'),
# /books/favorite/
url(r'^(?P<book_id>[0-9]+)/favorite/$', views.favorite, name='favorite'),
# /books/rate/
url(r'^(?P<book_id>[0-9]+)/rate/$', views.rate, name='rate'),
# /books/review/
url(r'^(?P<book_id>[0-9]+)/review/$', views.review, name='review'),
# /books/borrow/
url(r'^(?P<book_id>[0-9]+)/borrow/$', views.borrow, name='borrow'),
# books/user_profile/
url(r'user_profile/$', views.user_profile, name='user_profile'),
# books/edit_profile
url(r'edit_profile/$', views.edit_profile, name='edit_profile'),
# books/login_btn
url(r'login_btn/$', views.login_btn, name='login_btn'),
# books/show_users
url(r'show_users/$', views.show_users, name='show_users'),
# books/<username>/
url(r'^(?P<username>[a-z]*[A-Z]*[0-9]*)/$', views.follow_user, name='follow_user'),
# books/authors/
url(r'authors/$', views.authors, name='authors'),
]
我的观看功能是:
def authors(request):
all_authors = Authors.objects.all()
return render(request, 'books/authors.html', {'all_authors': all_authors})
def follow_user(request, username):
user_following = request.user
if user_following is not None:
user_to_be_followed = User.objects.get(username=username)
Follow.objects.add_follower(user_following, user_to_be_followed)
return render(request, 'books/test.html')
else:
return render(request, 'books/registration_form.html')
我的Html页面authors.html是:
{% extends 'books/base.html' %}
{% block title %}All authors{% endblock %}
{% block body %}
<div class="users-container container-fluid">
<!-- Books -->
<div class="row">
{% if all_authors %}
{% for author in all_authors %}
<div class="col-sm-4 col-lg-2">
<div class="thumbnail">
<h1>{{ author.name }}</h1>
</div>
</div>
<br>
{% endfor %}
{% else %}
<h3>Currently no authors available</h3>
{% endif %}
</div>
</div>
{% endblock %}
视图函数“follow_user”仅用于输入数据库,它没有与之关联的HTML页面。
test.html
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Title</title>
</head>
<body>
{% load friendshiptags %}
<h1> {% following request.user %} </h1>
</body>
</html>
我访问了类似问题的不同链接,但没有一个能解决我的问题。 link1:objects.all() query not working link2:Django objects.all() empty query set, not empty in shell
非常感谢帮助。谢谢
答案 0 :(得分:4)
/books/authors/
视图正在处理您对follow_user
的请求,因为它们都匹配,follow_user
模式高于authors
模式。
# books/<username>/
url(r'^(?P<username>[a-z]*[A-Z]*[0-9]*)/$', views.follow_user, name='follow_user'),
# books/authors/
url(r'authors/$', views.authors, name='authors'),
您可以通过更改正则表达式以使它们不发生冲突或将authors
模式移到follow_user
模式之上来解决此问题(请注意,这将阻止您使用{{username='authors'
模式跟踪用户1}})。
修复网址格式后,追溯表明您的follow_user
视图中存在问题,应该修复:
user_to_be_followed = User.objects.get(username=username)
如果数据库中可能存在用户,那么您也希望处理这种可能性。你可以捕获异常:
try:
user_to_be_followed = User.objects.get(username=username)
except User.DoesNotExist:
user_to_be_followed = None
或许您可以使用get_object_or_404
快捷方式:
from django.shortcuts import get_object_or_404
user_to_be_followed = get_object_or_404(User, username=username)
最后,请注意以下检查不正确:
user_following = request.user
if user_following is not None:
...
如果用户未登录,则request.user
将是匿名用户,不会是None
。您应该检查Django 1.10+中的if request.user.is_authenticated:
或早期版本中的if request.user.is_authenticated():
。
答案 1 :(得分:3)
您向我们展示的代码似乎很好,但在您的代码中的某个地方,您可以使用以下代码:
User.objects.get(username=user_id)
由于您尝试将id与用户名匹配,因此无法找到任何内容,而get()
找不到任何内容时会抛出异常。
您应该采取措施来捕捉错误,例如except User.DoesNotExists
并确定您的情况。