我正在使用jdk1.8的spring boot。我可以使用jaxb xml将Java对象Marshall转换为XML,但我想在XML输出上添加DOCTYPE。
当前xml输出:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
我想要的是:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE Example SYSTEM "example.dtd">
以下是我的JAXB
package com.example.demo.model;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;
import javax.xml.bind.PropertyException;
import java.io.File;
import java.io.StringWriter;
public class JAXBExample {
public String CreateXML() {
PDXIReq pdxiReq = new PDXIReq(new Header("KO0haj000", "SS_ASED",
"CTY_IPC"), new Request("ACT_ACTION", 20131106, 111816,
9181626L, 0,1024, "1AJHSYQW36276354"));
StringWriter sw = new StringWriter();
try {
JAXBContext jaxbContext = JAXBContext.newInstance(PDXIReq.class);
Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
// output pretty printed
jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
jaxbMarshaller.setProperty("com.sun.xml.internal.bind.xmlHeaders",
"\n<!DOCTYPE Example SYSTEM \"example.dtd\">");
jaxbMarshaller.marshal(pdxiReq, sw);
} catch (JAXBException e) {
e.printStackTrace();
}
return sw.toString();
}
}
答案 0 :(得分:1)
当我再次跑步时,上面的帖子已经正确了。
JAXBContext jaxbContext = JAXBContext.newInstance(PDXIReq.class);
Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
// output pretty printed
jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
jaxbMarshaller.setProperty("com.sun.xml.internal.bind.xmlHeaders",
"\n<!DOCTYPE Example SYSTEM \"example.dtd\">");