我知道这个问题在SO中有很多解决方案。但我仍然无法发现我的错误。以下是我的自助模式形式
<!DOCTYPE html>
<html lang="en">
<head>
<title>Bootstrap Example</title>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="assets/lib/bootstrap/css/bootstrap.min.css">
<script src="../asset/modal/js/jquery.min.js"></script>
<script src="assets/lib/bootstrap/js/bootstrap.min.js"></script>
</head>
<body>
<? if(isset($_POST["sendmail"]))
echo "Form 1 have been submitted";
?>
<div class="container">
<!-- Trigger the modal with a button -->
<!-- Modal -->
<div class="modal fade" id="myModal" role="dialog">
<div class="modal-dialog">
<? echo $token; ?>
<!-- Modal content-->
<form class="form-horizontal" role="form" method="post" name="sendmail" >
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title">Modal Header</h4>
</div>
<div class="modal-body">
<textarea rows="8" class="form-control"></textarea>
</div>
<div class="modal-footer">
<button type="submit" class="btn btn-default" >Send</button>
</div>
</div>
</form>
</div>
</div>
</div>
</body>
</html>
但每当我提交表单时,它都会重定向到我项目的索引页面。请帮助我发现我的错误。: - (
答案 0 :(得分:2)
是的,因为你没有把它指向任何地方......你需要写下这样的东西: -
<form class="form-horizontal" role="form" method="post" name="sendmail" action="page_name_here.php" >
因此您需要添加action="page_name_here.php">
如果您想留在同一页面上,请写下action="#">
更新: -
<button type="submit" class="btn btn-default" name="send">Send</button>
将name
添加到按钮send
,然后添加到Php中: -
<? if(isset($_POST["send"]))
echo "Form 1 have been submitted";
?>
这样,当您点击send
按钮时,表单中的所有内容都会提交,因为它的按钮为type=submit
答案 1 :(得分:0)
将其用于提交按钮。对于POST,您的按钮尚未被命名为sendmail
,因此信息将无法通过。
<? if(isset($_SERVER['REQUEST_METHOD'] == 'POST' ))
echo "Form 1 have been submitted";
?>
添加空行动,如同同一页所示
<form class="form-horizontal" role="form" method="post" name="sendmail" action="">