Question

这是我的JSON示例：

{"ID":2,"name":"Donatello","lastname":"Di Niccoló","age":23,"hobbies":["reading","dancing",{"sports":["rafting","baseball"]}],"address":{"street":"Tepito", "number":"77", "districts":"Benito Juárez", "country": "CDMX"}}

这是我的AVRO SCHEMA

{"type":"record","name":"myrecord","fields":[ 
{"name":"ID","type":"int"}, 
{"name":"name", "type": "string"},
{"name":"lastname", "type": "string"},
{"name":"age", "type": "int"},
{"name":"hobbies","type": {
        "type": "array",
        "items": {
        "type": "array", "items": "string",
        "type":"record","name":"myhobbies",
        "fields":[
                    {"name":"sports","type":{"type": "array", "items": "string"}}
                ]
}       }
},
{"name":"address","type":{"type":"record","name":"myaddress",
    "fields":[
    {"name":"street","type":"string"},
    {"name":"number","type":"string"},
    {"name":"districts","type":"string"},
    {"name":"country","type":"string"}
    ]

}
}
]}

我需要avro格式couse我想开始制作人员whit kafka但是当我开始它时，当我输入previos记录时出错。 Couse avro架构与记录不匹配。如何使它们匹配

Yeah Nitin Tripathi

{"type":"record","name":"myrecord","fields":[ 
{"name":"ID","type":"int"}, 
{"name":"name", "type": "string"},
{"name":"lastname", "type": "string"},
{"name":"age", "type": "int"},
{"name":"hobbies","type": {
        "type": "array",
        "items": {
        "type":"record","name":"myhobbies",
        "fields":[
                    {"name":"sports","type":{"type": "array", "items": "string"}}
                ]
}       }
},
{"name":"address","type":{"type":"record","name":"myaddress",
    "fields":[
    {"name":"street","type":"string"},
    {"name":"number","type":"string"},
    {"name":"districts","type":"string"},
    {"name":"country","type":"string"}
    ]

}
}
]}

我试过了，但它不起作用:(

Answer 1

数组使用类型名称＆＃34;数组＆＃34;并且支持单个属性，但是，爱好的模式混合了字符串和myhobbies类型

如何为复杂的json文档定义avro架构？

1 个答案: