tableList在哪里变为空？为什么？

Question

我正在实现一个适配器来获取List和Hashmap，并将它们分别转换为可扩展ListView的头和子项。在构造函数的Log语句中，它显示值正在成功传输到本地列表。但随后它突然变为零。

我无法确定哪里出了问题，哪里出了问题。请帮忙。

以下是Adapter类的代码：

array1

这是我的日志：

Answer 1

您在打印地图时删除了该项目，

# Sorted (descending) => 810, 810, 738, 738, 90, 82, 82, 10

from queue import PriorityQueue

def karmarkar_karp_partition(arr):
    pqueue = PriorityQueue()

    for e in arr:
        pqueue.put_nowait((-e, e))

    for _ in range(len(arr)-1):
        _, first = pqueue.get_nowait()
        _, second = pqueue.get_nowait()
        diff = first - second
        pqueue.put_nowait((-diff, diff))

    return pqueue.get_nowait()[1]

只需删除它就能正常工作。

public void insertAtIndex(int x, int index){
    Element n = new Element(); 
    n.val = x; 

    if (head == null){ // If the list is empty
        head = n; // we insert the Element n as the first element
    }
    else{   
        Element h = head; // our current element we are looking at
        int currentIndex = 0;
        while (h.next!=null && currentIndex < index) { // increment until we reach the correct index
            h = h.next; // our Element h becomes the next Element added to the list        
            currentIndex++;
        }
        Element tail = h.next; // store the rest of the list in a temp variable, tail
        h.next = n; // we've reached the right index and/or the end, so add the element n here
        n.next = tail // reattach the tail 
    }
}

Answer 2

在您的方法Error:(9, 15) scrutinee is incompatible with pattern type; found : Seq[A] required: Array[Int] case Seq( 中，const lookup = (firstName, prop) => { const person = contacts.find(p => p.firstName === firstName); if (!person) { return 'No such contact'; } if (!person[prop]) { return 'No such property'; } return person[prop]; }; const person = lookup('Kristian', 'likes'); 块中的最后一个语句是

printMap()

此语句可能不会导致while，但会从 it.remove(); // avoids a ConcurrentModificationException 中删除当前条目。所以执行后

Exception

<{1}} HashMap中的

tableList 将为空。