我正在使用Microsoft SQL Server 2014(SP2)。
我有一串以下格式的文字:
12/07/17 - Amount to pay £580.00 = Rent plus £55.58 per month - MC
值和内容会发生变化,但总是采用这种格式。
如何在单词pay之后提取数字值。在这种情况下它是'£580.00',但价值可能会有所不同,如'£20.00'或'£7.50'等。
由于
答案 0 :(得分:2)
我喜欢John关于使用iTVF的想法,但是不需要承担基于计数器的分配器的费用。当你需要根据分隔符将一个字符串解析成很多行时,它们会非常棒,但是对于这样的事情总是过分杀人。
这是一个应该更快,更有效的替代方案......
CREATE FUNCTION dbo.tfn_ExtractPayAmount
/* =========================================================================
Extracts the monetary amount following the 1st occurrence of the word "pay".
========================================================================= */
(
@String VARCHAR(800)
)
RETURNS TABLE WITH SCHEMABINDING AS
RETURN
SELECT
RetValue = SUBSTRING(@String, sp.StartPosition, ISNULL(ep.EndPosition - sp.StartPosition, 0))
FROM
( VALUES (CHARINDEX(' pay ', @String, 1) + 5) ) sp (StartPosition)
CROSS APPLY ( VALUES (IIF(sp.StartPosition = 5, NULL, CHARINDEX(' ', @String, sp.StartPosition + 1))) ) ep (EndPosition);
GO
HTH,Jason
答案 1 :(得分:1)
如果对TVF(表值功能)开放,请考虑以下
厌倦了提取字符串(left,right,charindex,patindex,...)我修改了一个解析函数来接受两个不相似的参数。在这种情况下'pay '
和' '
。
示例强>
Declare @YourTable table (ID int,SomeCol nvarchar(500))
Insert Into @YourTable values
(1,'12/07/17 - Amount to pay £580.00 = Rent plus £55.58 per month - MC')
Select A.*
,B.RetVal
From @YourTable A
Cross Apply [dbo].[udf-Str-Extract](A.SomeCol,'pay ',' ') B
Where try_convert(money,B.RetVal) is not null
<强>返回强>
感兴趣的UDF
CREATE FUNCTION [dbo].[udf-Str-Extract] (@String varchar(max),@Delimiter1 varchar(100),@Delimiter2 varchar(100))
Returns Table
As
Return (
with cte1(N) As (Select 1 From (Values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) N(N)),
cte2(N) As (Select Top (IsNull(DataLength(@String),0)) Row_Number() over (Order By (Select NULL)) From (Select N=1 From cte1 N1,cte1 N2,cte1 N3,cte1 N4,cte1 N5,cte1 N6) A ),
cte3(N) As (Select 1 Union All Select t.N+DataLength(@Delimiter1) From cte2 t Where Substring(@String,t.N,DataLength(@Delimiter1)) = @Delimiter1),
cte4(N,L) As (Select S.N,IsNull(NullIf(CharIndex(@Delimiter1,@String,s.N),0)-S.N,8000) From cte3 S)
Select RetSeq = Row_Number() over (Order By N)
,RetPos = N
,RetVal = left(RetVal,charindex(@Delimiter2,RetVal)-1)
From (
Select *,RetVal = Substring(@String, N, L)
From cte4
) A
Where charindex(@Delimiter2,RetVal)>1
)
/*
Max Length of String 1MM characters
Declare @String varchar(max) = 'Dear [[FirstName]] [[LastName]], ...'
Select * From [dbo].[udf-Str-Extract] (@String,'[[',']]')
*/
编辑 - 说明多个值的回归
Select A.*
,B.RetVal
From @YourTable A
Cross Apply [dbo].[udf-Str-Extract](A.SomeCol,'£',' ') B
Where try_convert(money,B.RetVal) is not null
<强>返回强>