Question

如何减少执行相同操作的2个函数？实际上，使用数组score添加数组score2是个问题。

def printPoint1(name, point, score):
  for i in range(len(name)):
    print("Name : " + name[i] + " Your score is of " + str(point[i]) + " : " + str(goal[i]) + " goals. ")
  score.append(point[i])

def printPoint2(name, point, score2):
  for i in range(len(name)):
    print("Name : " + name[i] + " Your score is of " + str(point[i]) + " : " + str(goal[i]) + " goals. ")
  score2.append(point[i])

Answer 1

答案是不要创建两个完全相同的功能。只需创建一个功能，即可传递score或score2。

Answer 2

一个功能的工作！不需要复制每个要处理的新变量的代码。如果你定义：

def printPoint1(name, point, score):
  for i in range(len(name)):
    print("Name : " + name[i] + " Your score is of " + str(point[i]) + " : " + str(goal[i]) + " goals. ")
  score.append(point[i])

然后您可以根据需要调用您的函数：

printPoint1(Var1, Var2, Var3)

使用任何不同的Var1，Var2，Var3您应该尊重每个type（int，float，list，string等）你运作的变量将会处理

减少我的功能

2 个答案: