Question

我正在尝试构造泛型类型的实例并在该实例上调用方法。然后返回方法的结果。

var genericType = typeof(GenericType<>).MakeGenericType(typeof(TOutput));
il.DeclareLocal(genericType);
var instanceMethod = genericType.GetMethod("MethodName", new Type[0]);
il.Emit(OpCodes.Call, instanceMethod);
il.Emit(OpCodes.Ret);

我一直收到'System.InvalidProgramExecution'异常。

GenericType类看起来像这样

public class GenericType<T>
{
    public T MethodName()
    {
        ...
    }
}

Answer 1

找出需要为特定函数发出的IL的简单方法是手动编写要生成的代码，然后使用ILDASM查看编译器创建的IL。

以下是一个例子......

要复制的C＃方法......

public static TOutput DoWork()
{
    var generic = new GenericType<TOutput>();
    var ret = generic.MethodName();
    return ret;
}

生成IL ...

.method public hidebysig static class App.TOutput 
DoWork() cil managed
{
    // Code size       15 (0xf)
    .maxstack  1
    .locals init ([0] class App.GenericType`1<class App.TOutput> generic,
            [1] class App.TOutput 'ret')
    IL_0000:  newobj     instance void class App.GenericType`1<class App.TOutput>::.ctor()
    IL_0005:  stloc.0
    IL_0006:  ldloc.0
    IL_0007:  callvirt   instance !0 class App.GenericType`1<class App.TOutput>::MethodName()
    IL_000c:  stloc.1
    IL_000d:  ldloc.1
    IL_000e:  ret
} // end of method Program::DoWork

有关如何发出和调用此IL的示例...

var retType = typeof(TOutput);
var type = typeof(GenericType<>);
var genericType = type.MakeGenericType(retType);
var constructor = genericType.GetConstructor(Type.EmptyTypes);
var methodDef = genericType.GetMethod("MethodName", Type.EmptyTypes);

var newMethod = new DynamicMethod("MyMethod", retType, Type.EmptyTypes);
var generator = newMethod.GetILGenerator();
generator.DeclareLocal(genericType);
generator.DeclareLocal(retType);
generator.Emit(OpCodes.Newobj, constructor);
generator.Emit(OpCodes.Stloc_0);
generator.Emit(OpCodes.Ldloc_0);
generator.EmitCall(OpCodes.Callvirt, methodDef, null);
generator.Emit(OpCodes.Stloc_1);
generator.Emit(OpCodes.Ldloc_1);
generator.Emit(OpCodes.Ret);

var ret = newMethod.Invoke(null, null);
Console.WriteLine(ret); // App.TOutput

支持课程......

public class GenericType<T> where T : new()
{
    public T MethodName()
    {
        return new T();
    }
}
public class TOutput
{
}

Answer 2

试试这段代码：

var il = mbuilder.GetILGenerator();
var genericType = typeof(GenericType<>).MakeGenericType(typeof(TOutput));
il.Emit(OpCodes.Newobj, genericType.GetConstructor(Type.EmptyTypes));
il.EmitCall(OpCodes.Callvirt, genericType.GetMethod("MethodName", Type.EmptyTypes), null);
il.Emit(OpCodes.Ret);

ILGenerator实例化对象和调用实例方法

2 个答案: