Question

这是我正在做的事情的前提：

我有一个程序在后台运行，一直是套接字服务器。

我创建了一个调用php脚本（使用AJAX）的网站，该脚本打开客户端套接字，连接到服务器，发送请求并接收它，然后回显它。

这个回声是响应是＆＃39;返回值＆＃39;对于我的AJAX脚本。

这就是这个问题：

当我单击按钮时，信息会发送，但有时，信息永远不会返回到站点。

我知道正在通过服务器处理请求，因为我可以看到请求在服务器端运行完成。
我知道服务器端的信息正在发送到客户端（网站），因为我有一个代码，用于检查数据是否已从服务器端成功发送。
有时会通过相应的响应客户端发送请求（来自服务器的信息的警告弹出窗口）。

网站代码：

<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST">
<input type="submit" class="button" name="weather" value="weather" />
<input type="submit" class="button" name="time" value="time" />
<input type="submit" class="button" name="date" value="date" />
</form>

jQuery代码：

$(document).ready(function(){

$('.button').click(function(){
    var clickBtnValue = $(this).val();
    var ajaxurl = 'php/portserverclient.php',
    dataSend =  {'action': clickBtnValue};

    $.post(ajaxurl, dataSend, function (response) {
        // Response div goes here.
        //$('#servermessage').val($('#servermessage').val()+response); 
        alert(response);
    });
});

PHP代码：

<?php

// -------------------------------------
// ----- Get Information Sent from Site
// -------------------------------------

if (isset($_POST['action']))
    {
         switch ($_POST['action']) {
            case 'weather':
                $in = "3";
                $request = "Weather";
                break;
            case 'time':
                $in = "2";
                $request = "Time";
                break;
            case 'date':
                $in = "1";
                $request = "Date";
        }
    }
else
{
    $in = "3";
    $request = "Weather";
}

// -------------------------------------
// ----- Open Client Side Socket
// -------------------------------------    

error_reporting(E_ALL);

$A1 = "Starting TCP/IP Connection... \n";

/* Get the port for the WWW service. */
$service_port = 51713;

/* Get the IP address for the target host. */
$address = '192.168.8.129';

/* Create a TCP/IP socket. */
$socket = socket_create(AF_INET, SOCK_STREAM, 0);
if ($socket === false) 
{
    $A2 = "socket_create() failed: reason: " . socket_strerror(socket_last_error()) . "\n";
    exit;
} 
else {
    $A2 = "Socket Created...OK.\n";
}
socket_set_option($socket, SOL_SOCKET, SO_REUSEADDR, 1);
socket_set_option($socket, SOL_SOCKET, SO_RCVTIMEO, array('sec' => 5, 'usec' => 0));
socket_set_option($socket, SOL_SOCKET, SO_SNDTIMEO, array('sec' => 5, 'usec' => 0));

$A3 = "Attempting to connect to '$address' on port '$service_port'...";
$result = socket_connect($socket, $address, $service_port);
if ($result === false) 
{
    $A4 = "socket_connect() failed.\nReason: ($result) " . socket_strerror(socket_last_error($socket)) . "\n";
    exit;
} 
else 
{
    $A4 = "OK.\n";
}

// -------------------------------------
// ----- Send message through socket
// -------------------------------------

$A5 = "Sending $request request...";
$sent = socket_write($socket, $in, strlen($in));
$A6 = "OK.\n";

// -------------------------------------
// ----- Receive response through socket
// -------------------------------------

$out = ' ';
do{$out = socket_read($socket, 20, PHP_NORMAL_READ) ;}
while($out === false);

// -------------------------------------
// ----- Close Client Side Socket
// -------------------------------------

$A7 = "Closing socket...";
$A8 = "OK.\n";
echo "\n From PHP END: ", $A1,$A2,$A3,$A4,$A5,$A6,$A7,$A8,"Message: ", $out,"\n";

socket_shutdown($socket,2);
socket_close($socket);

exit;
?>

C ++服务器端代码：

//---- read buffer ---
    sizeofread = read(newsockfd, msg, 20);
    if (sizeofread <= 0 || msg[0] == 0x0A || msg[0] == 0x0D || msg[0] == 0x00) 
    {
        // Stops any buggy send (size of read <= 0)
        // Stops terminal from sending new line (0x0A & 0x0D) after each press enter
        // Stops terminal from sending 0 constantly (0x00)
    }
    else
    {
        printf("Received from TCP: %s \n",msg);

        //--- Send to Arduino ---
        printf( "Sending to Arduino: %s \n", msg);
        write( uartt, msg, 20 );
        delay(50);  // Here to account for how long it takes to send & receive 20 bytes at 9600 Baud

        //--- Receive from Arduino ---
        while (counter <= 2 && found == false)
        {
            if ( !( msgLength = serialDataAvail(uartt) ))
            {
                printf("Nothing to read \n");
                delay(1071); // Here to account for how long it takes to receive 1024 bytes at 9600 Baud
                counter++;
            }
            else
            {
                found = true;
                read(uartt, msg, msgLength);
                msg[msgLength] = 0;
                if (write(newsockfd, msg, 20) < 0)
                {
                    printf("Failed to send to socket \n");
                }
                else
                {
                    printf("Succesfully sent to socket \n");
                }
                printf("From the Arduino: ");
                printf("%s \n", msg);
            }
            delay(100);
            serialFlush(uartt);
        }
        counter = 0;
        found = false;
        close(newsockfd);
        goto repeat;
    }

Answer 1

原来这个谜语的答案是我需要禁用提交按钮默认事件。通常，在HTML中，提交按钮刷新页面，必须停止。

这样就停止了：

$('.button').click(function(event){ 
    var clickBtnValue = $(this).val();
    var ajaxurl = 'php/portserverclient.php',
    dataSend =  {'action': clickBtnValue};

    $.post(ajaxurl, dataSend, function (response) {
        alert(response);
    });

    event.preventDefault();
});

谢谢你们

从AJAX调用的PHP脚本返回值并不会一直显示

1 个答案: