我的产品表包含name
和no_of_sell
列。
我想根据产品表中的no_of_sell
列获得最高的5个销售产品。
我如何将它与查询构建器一起使用?
$propular_products = DB::table('users')
->join('products','products.auth_id','users.id')
->select('products.*')
->orderBy('products.no_of_sell', 'desc')
->where('products.status','=','1')
->paginate(5);
假设products
表:
name no_of_sell
x 6
y 9
z 10
t 23
u 3
h 11
r 5
我想找到
products list of 5 max no_of_sell ie, x y z t h
答案 0 :(得分:0)
因此,如果我在列no_of_sell
中正确理解它是一个int。我应该写如下:
$best_sell = DB::table('products')
->orderBy('no_of_sell', 'desc')
->limit(5)
->where('products.status','=','1')
->paginate(4)
->get();
https://laravel.com/docs/5.4/queries#retrieving-results https://laravel.com/docs/5.4/queries#ordering-grouping-limit-and-offset
答案 1 :(得分:0)
$best_sell = DB::table('products')
->select('no_of_sell')
->where('products.status','=','1')
->orderBy('no_of_sell', 'desc')
->paginate(4);
答案 2 :(得分:0)
$best_sell = DB::table('products')
->select() // your selection criteria
->where('products.status','=','1')
->take(5)->get();