Question

我有两个阵列，余额和提交

balances =  [
{name: 'vacation', value: ''21},
{name: 'account', value: '200'},
{name: 'order', value: '15'},
]

commits = [
{balanceName: 'vacation', paramName: 'number of days'},
{balanceName: 'order', paramName: 'number of items'}
]

我想删除未提交的表单余额，在此示例中，我想从余额中删除帐户值，因为它不在任何提交的balanceName中我怎么能通过下划线或任何其他库

来做到这一点

Answer 1

你可以使用var balances = [ {name: 'vacation', value: '21'}, {name: 'account', value: '200'}, {name: 'order', value: '15'} ] var commits = [ {balanceName: 'vacation', paramName: 'number of days'}, {balanceName: 'order', paramName: 'number of items'} ] balances2= _.filter(balances,(b)=>commits.map(c=>c.balanceName).indexOf(b.name)>-1); console.log("using shorter syntax"); console.log(balances) //OR balances= _.filter(balances,function(b){return commits.map(function(c){return c.balanceName}).indexOf(b.name)>-1}); console.log("ES5 syntax"); console.log(balances2)这样做：

＆＃13;

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＆＃13;

_.filter

＆＃13;

_.find将返回符合条件的所有条目。例如_.map将只返回第一个条目。我还使用了c=>c.balanceName，它通过使用transform函数（在我的例子<?php // We'll be outputting a PDF header('Content-Type: application/pdf'); // It will be called downloaded.pdf header('Content-Disposition: attachment; filename="downloaded.pdf"'); // The PDF source is in original.pdf readfile('original.pdf'); ?>中）将具有多个属性的数组转换为其他数组。

Answer 2

不需要图书馆。

function contains(commits, name)
{
    commits.some(function(x) { return x.balanceName === name});
}

for(blance in balances) {
    if (contains(commits, balance.name){
        // Remove balance
    }
}

下划线如何比较两个数组？

2 个答案: