Question

我在我的日期选择器中选择了一个日期，但它不需要并提醒＆＃34;请选择日期格式的日期dd-mm-yyyy＆＃34;当我提交。

function get_invoice()
{
    var client_id = $('#client_name').val();
    $.ajax({
        type: "POST",
        dataType: "json",
        data:{'client_id':client_id},
        url: "<?= site_url('master/get_invoice') ?>",
        success: function (data) {
            var table = document.getElementById("item-tables");
            $("#item-tables").find("tr:not(:first)").remove();
    //      $("#tbodyid").empty();
            var j=1;
            var today = new Date();
            var dd = today.getDate();
            var mm = today.getMonth()+1; //January is 0! 
            var yyyy = today.getFullYear();
            if(dd<10){
                dd='0'+dd;
            } 
            if(mm<10){
                mm='0'+mm;
            } 
            var today = dd+'-'+mm+'-'+yyyy;
            var date = $('.datepicker').datepicker( {autoclose: true,dateFormat: 'dd-mm-yy' } );
            for (var i = 0; i < data.invoice.length; i++){
                var rowCount = table.rows.length;
                var row = table.insertRow(rowCount);
                var balance = parseFloat(data.invoice[i].amount)-parseFloat(data.invoice[i].paid);
                row.insertCell(0).innerHTML= '<input type="text" class="form-control date datepicker has Datepicker  input-sm" size="16" name="date'+j+'" id="date'+j+'" value="">';
                row.insertCell(1).innerHTML= '<input type="text" class="form-control" name="invoice_id'+j+'" id="invoice_id'+j+'" value = "' + data.invoice[i].invoice_code +'" readonly>';
                j++;
            }
            $('.datepicker').datepicker( {autoclose: true,dateFormat: 'dd-mm-yy' } );
        }
    });
}

Answer 1

试试这个

var date = $('.datepicker').datepicker({ dateFormat: 'dd-mm-yy' }).val();

Answer 2

不确定是否是原因 - 但是你的datepicker dateFormat声明的格式与“today”变量的格式不同。尝试修改你的dateFormat为全年（yyyy），如下所示

reprex_as_pdf <- system2(
    command = "texi2pdf",
    args = c("reprex.tex", "-o", "/dev/stdout"),
    stdout = TRUE, stderr = TRUE
)

DatePicker在jQuery中显示错误

2 个答案: