我正在尝试通过一个正常的sql语句来获得分区的总和但是代码不起作用。技术:SQL Server 2014
以下是代码:
select
ZABF$,ZUNR$,ZONR$,FPLN$,ZSTR$,right(left(GABS$,3),2) as Region
,SUM(Nettobetrag) AS NettoUmsatz
,SUM(BRUTTOBETRAG) AS BruttoUmsatz
,SUM(Nettobetrag) over (partition by ZABF$,ZUNR$,ZONR$,FPLN$,right(left(GABS$,3),2))
from
ArchivZBEW.PROD.sFCTS_G195
where
NETTOBETRAG<>0 and right(left(GABS$,3),2)<>'65'
and UTYP$ in('K','M','P')
group by
ZABF$,ZUNR$,ZONR$,FPLN$,ZSTR$,right(left(GABS$,3),2)
正如您所看到的,我尝试获得第一行中所有列的输出,然后是不同的总和。 NettoUmsatz和Bruttoumsatz工作得很好,就像预期的那样 - 但现在我需要另一个忽略“ZSTR $”字段的总和。我把这个查询作为CTE的一部分,所以在这个语句中使用它会很好,否则我必须加入表两次并且语句变得很慢。
ErrorCode :(德语):
Die ArchivZBEW.PROD.sFCTS_G195.NETTOBETRAG-Spalte ist in derAuswahllistengültig,da sie nicht in einer Aggregatfunktion und nicht in der GROUP BY-Klausel enthalten ist。
感谢谷歌翻译:
archiveZBEW.PROD.sFCTS_G195.NETTOBETRAG列在选择列表中无效,因为它不包含在聚合函数中,并且不包含在GROUP BY子句中。
答案 0 :(得分:5)
在GROUP BY中使用SUM()OVER()没有特别的问题,但是你可能会因为与OVER相关的SUM()的存在而感到困惑,并且忘记它只是需要的另一列发表自己,或在
小组中提到这不起作用:
SELECT
a,
SUM(b),
SUM(c) OVER(PARTITION BY a) --this wont work: c is not mentioned in GROUP BY and this column is not an aggregate in the GROUP BY sense
FROM
table
GROUP BY
a
你要么:
SELECT
a,
SUM(b),
SUM(c) OVER(PARTITION BY a)
FROM
table
GROUP BY
a, c --make c something you group by
或者:
SELECT
a,
SUM(b),
SUM(SUM(c) OVER(PARTITION BY a)) --inner sum is overed, outer is groupbyed
FROM
table
GROUP BY
a
或者:
SELECT
a,
SUM(b),
SUM(SUM(c)) OVER(PARTITION BY a) --inner SUM is groupbyed, outer sum is overed
FROM
table
GROUP BY
a
答案 1 :(得分:3)
多数民众赞成 - 谢谢你们 - 这是我的一个重大思想 - 这就是结果:
select DISTINCT
ZABF$,ZUNR$,ZONR$,FPLN$,ZSTR$,right(left(GABS$,3),2) as Region
,SUM(Nettobetrag) over (partition by ZABF$,ZUNR$,ZONR$,FPLN$,ZSTR$,right(left(GABS$,3),2)) AS NettoUmsatz
,SUM(BRUTTOBETRAG) over (partition by ZABF$,ZUNR$,ZONR$,FPLN$,ZSTR$,right(left(GABS$,3),2)) AS BruttoUmsatz
,SUM(Nettobetrag) over (partition by ZABF$,ZUNR$,ZONR$,FPLN$,right(left(GABS$,3),2))
from
ArchivZBEW.PROD.sFCTS_G195
where
--NETTOBETRAG<>0
right(left(GABS$,3),2)<>'65'
and UTYP$ in('K','M','P')
答案 2 :(得分:0)
您可以执行以下更改以使代码正常工作:
select
ZABF$,ZUNR$,ZONR$,FPLN$,ZSTR$,right(left(GABS$,3),2) as Region
,SUM(Nettobetrag) AS NettoUmsatz
,SUM(BRUTTOBETRAG) AS BruttoUmsatz
-- ,SUM(Nettobetrag) over (partition by ZABF$,ZUNR$,ZONR$,FPLN$,right(left(GABS$,3),2)) --commented as this is same as nettoUmsatz
from
ArchivZBEW.PROD.sFCTS_G195
where
--NETTOBETRAG<>0 and --sum has to be in having
right(left(GABS$,3),2)<>'65'
and UTYP$ in('K','M','P')
group by
ZABF$,ZUNR$,ZONR$,FPLN$,ZSTR$,right(left(GABS$,3),2)
having SUM(Nettobetrag) <> 0 --you might require this