Question

我的程序应该解决方程式。我刚刚添加了区分+和 - 的部分。这些方程式非常简单。（如2x = 4 + 2或4x = 1-4）这是我的代码：

from tkinter import *
import time
form = Tk()
form.title('Hello')
auff = Label(form, text='Put in Equation!')
rein = Entry(form)
lein = Entry(form)
istg = Label (form, text='=')
stop = Button(form, text='Stop',  command=form.destroy)
start = Button (form, text='Compute')
erge = Label (form, text='')

r = rein.get()
l = lein.get()

def operation (event):
    if ('+' or '-' in l):
        if '+' in l:
            l1,l2 = l.split ('+')
            if ('x' not in l1 or l2):
                ll = l1 + l2
                return ll
        if '-' in l:
            l1,l2 = l.split ('-')
            if ('x' not in l1 or l2):
                ll = l1 - l2
                return ll
    if ('+' or '-' in r):
        if '+' in r:
            r1,r2 = r.split ('+')
            if ('x' not in r1 or r2):
                rr = r1 + r2
                return rr
        if '-' in r:
            r1,r2 = r.split ('-')
            if ('x' not in r1 or r2):
                rr = r1 - r2
                return rr

def einfach (event):
    r = rein.get()
    l = lein.get()
    x = 'x'
    if x in l:
        operation (event)
        lr = int(lr)
        end = rr/lr
        end = int (end)
        erge['text']= 'x = {}'.format(end)
    elif x in r:
        operation (event)
        rl = int(rl)
        end = ll/rl
        end = int(end)
        erge['text']='x = {}' .format(end)

start.bind('<Button-1>', einfach)
auff.grid(row = 0, column = 1)
rein.grid(row = 1, column = 2)
istg.grid(row = 1, column = 1)
lein.grid(row = 1, column = 0)
erge.grid(row = 4, column = 1)
start.grid(row = 2, column = 1)
starts.grid(row = 3, column = 1)
erkl1.grid(row = 5, column = 1)
erkl2.grid(row = 6, column = 1)
erkl3.grid(row = 7, column = 1)
erkl4.grid(row = 8, column = 1)
stop.grid(row = 9, column = 1)


start.mainloop()

我可能会添加错误：没有错误消息但是当您按下计算时它不会执行任何操作。

提前致谢，

香蕉

Answer 1

您的代码有几个问题。

您编写while语句的方式不符合您的预期。

声明：

while '+' or '-' in l:

并不意味着当+或-位于l时，请执行某些操作。相反，这意味着当+为True或-位于l时，则执行某些操作。因为+总是为True，所以while语句将始终处于活动状态。

你应该写的是：

while '+' in l or '-' in l:

这与以下几行：+中的l或-中l的{{1}}然后执行某些操作。

您可能需要查看与解决x相关的一些堆栈溢出帖子。

这里有一篇你可能会发现有帮助的帖子How can I solve equations in Python?

Python程序没有启动（Tkinter）

1 个答案: