Question

嗨我在数据库中插入数据时遇到此错误请告诉我symfony中的新问题在哪里

“类型为”AppBundle \ Entity \ Class_cat \“的预期值关联字段\“AppBundle \ Entity \ User＃$ class_cat \”，得到了 “整数”代替。“， “class”：“Doctrine \ ORM \ ORMInvalidArgumentException”

这是用户实体

namespace AppBundle\Entity;

use Doctrine\ORM\Mapping as ORM;

/**
 * User
 *
 * @ORM\Table(name="user")
 * @ORM\Entity(repositoryClass="AppBundle\Repository\UserRepository")
 */
class User
{
    /**
     * Constructor
     */
    public function __construct()
    {
        $this->class_cat = new \Doctrine\Common\Collections\ArrayCollection();
    }

    /**
     * @var int
     *
     * @ORM\Column(name="id", type="integer")
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="AUTO")
     */
    private $id;

    /**
     * @var string
     *
     * @ORM\Column(name="name", type="string", length=255)
     */
    private $name;

    /**
     * @var string
     *
     * @ORM\Column(name="role", type="string", length=255)
     */
    private $role;


    /**
     * @ORM\ManyToOne(targetEntity="Class_cat", inversedBy="users")
     * @ORM\JoinColumn(name="class_id", referencedColumnName="id")
     */
    private $class_cat;

    /**
     * Get id
     *
     * @return int
     */
    public function getId()
    {
        return $this->id;
    }

    /**
     * Set name
     *
     * @param string $name
     *
     * @return User
     */
    public function setName($name)
    {
        $this->name = $name;

        return $this;
    }

    /**
     * Get name
     *
     * @return string
     */
    public function getName()
    {
        return $this->name;
    }

    /**
     * Set role
     *
     * @param string $role
     *
     * @return User
     */
    public function setRole($role)
    {
        $this->role = $role;

        return $this;
    }

    /**
     * Get role
     *
     * @return string
     */
    public function getRole()
    {
        return $this->role;
    }

    /**
     * @return mixed
     */
    public function getClassCat()
    {
        return $this->class_cat;
    }

    /**
     * @param mixed $class_cat
     */
    public function setClassCat($class_cat)
    {
        $this->class_cat = $class_cat;
    }

这是class_cat enity

class Class_cat {

    /**
     * Constructor
     */
    public function __construct()
    {
        $this->users = new \Doctrine\Common\Collections\ArrayCollection();
    }

    /**
     * @var int
     *
     * @ORM\Column(name="id", type="integer")
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="AUTO")
     */
    private $id;

    /**
     * @var string
     *
     * @ORM\Column(name="class_name", type="string", length=255)
     */
    private $className;

    /**
     * @ORM\OneToMany(targetEntity="User", mappedBy="class_cat")
     */
    protected $users;

    /**
     * Get id
     *
     * @return int
     */
    public function getId()
    {
        return $this->id;
    }

    /**
     * Set className
     *
     * @param string $className
     *
     * @return Class_cat
     */
    public function setClassName($className)
    {
        $this->className = $className;

        return $this;
    }

    /**
     * Get className
     *
     * @return string
     */
    public function getClassName()
    {
        return $this->className;
    }


    public function getUsers()
    {
        return $this->users;
    }

    /**
     * @param mixed $users
     */
    public function setUsers($users)
    {
        $this->users = $users;
    }

这是控制器代码

>  public function postAction(Request $request)
>     {
>         $data = new User;
>         $name = $request->get('name');
>         $role = $request->get('role');
>         $class = $request->get('class_id');
>         if (empty($name) || empty($role) || empty($class)) {
>             return new View("NULL VALUES ARE NOT ALLOWED", Response::HTTP_NOT_ACCEPTABLE);
>         }
>         $data->setName($name);
>         $data->setRole($role);
>         $data->setClassId(1);
>         $em = $this->getDoctrine()->getManager();
>         $em->persist($data);
>         $em->flush();
>         return new View("User Added Successfully", Response::HTTP_OK);
>     }

Answer 1

您需要传递不是id的实体，例如：

$em = $this->getDoctrine()->getManager();
$classCat = $em->getRepository('AppBundle:ClassCat')->find(1);
$data->setClassCat($classCat);

Answer 2

嗨，您无需传递整数值，您需要传递Class_cat类的对象。当您将任何实体字段映射到任何其他实体时，symfony需要设置对象。因此，您的解决方案很容易尝试这样的事情：

public function postAction(Request $request){
    $em = $this->getDoctrine()->getManager();
    $data = new User;
    $name = $request->get('name');
    $role = $request->get('role');
    $class = $request->get('class_id');

    if (empty($name) || empty($role) || empty($class)) {
        return new View("NULL VALUES ARE NOT ALLOWED", 
        Response::HTTP_NOT_ACCEPTABLE);
    }

    $classCat = $em->getRepository('AppBundle:ClassCat')->find($class);
    $data->setName($name);
    $data->setRole($role);
    $data->setClassId($classCat);
    $em->persist($data);
    $em->flush();
   return new View("User Added Successfully", Response::HTTP_OK);
}

Answer 3

而不是整数值使用这样的对象：

$data->setClassId(1);

$em = $this->getDoctrine()->getManager();

$classCat = $em->getRepository('AppBundle:ClassCat')->find(1);

$data->setClassCat($classCat);

AppBundle \\ Entity \\ User＃$ class_cat \“，得到\”整数\“而不是

3 个答案: