大家好, 首先我想告诉大家我是CSharp的新手,这就是为什么我不知道我创建MySQL连接的方式是错误的,所以我必须用Prepared Statement来改变它。请善待!
这是我尝试使其有效的方法。
[HttpPost]
public ActionResult ValidatesLogin (User eUser)
{
var Email = eUser.Email;
var Password = eUser.Password;
try
{
MySqlCommand cmd = MySqlConn.cmd;
cmd = new MySqlCommand(" from User " + "WHERE Email=@email " + "AND Password=@password",
MySqlConn.conn);
cmd.Prepare();
cmd.Parameters.AddWithValue("@email", username);
cmd.Parameters.AddWithValue("@password", password);
int result = (int)cmd.ExecuteReader();
//encrypting the login user password
//the encrypter and decrypter must have same key which is 'kahat' below
var encryptpassword = EncryptHelper.EncryptString(eUser.Password, "kahat");
// Returns true when username and password match:
if (result > 0)
{
System.Web.Security.FormsAuthentication.SetAuthCookie(eUser.Email, false);
return RedirectToAction("Index", "Index", new { area = "Index" });
}
else
{
TempData["Message"] = "Login failed. Email or password supplied doesn't exist.";
return View("Index");
}
}
catch (Exception ex)
{
return ThrowJsonError(ex);
}
}
以下代码是我的实际连接,效果非常好。
[HttpPost]
public ActionResult Validate(User eUser)
{
try
{
//Pull email and password from login page
var Email = eUser.Email;
var Password = eUser.Password;
//Pull first email and password from database
var currentUser = this.rpGeneric.Find<User>(" from User WHERE Email=:email ", new string[] { "email" }, new object[] { Email }).FirstOrDefault();
//encrypting the login user password
//the encrypter and decrypter must have same key which is 'kahat' below
var encryptpassword = EncryptHelper.EncryptString(eUser.Password, "kahat");
//Comparing user password in login page and current password in db
if (currentUser != null && encryptpassword.Equals(currentUser.Password, StringComparison.Ordinal) && currentUser.EmailConfirmed == true)
{
System.Web.Security.FormsAuthentication.SetAuthCookie(eUser.Email, false);
return RedirectToAction("Index", "Index", new { area = "Index" });
}
else
{
TempData["Message"] = "Login failed. Email or password supplied doesn't exist.";
return View("Index");
}
}
catch (Exception ex)
{
return ThrowJsonError(ex);
}
}
答案 0 :(得分:1)
您的SQL查询不完整。
cmd = new MySqlCommand(" from User " + "WHERE Email=@email " + "AND Password=@password",
MySqlConn.conn);
你没有告诉MySql你想要它做什么,你需要添加&#34;选择&#34;子句和您从表中选择的列名:
cmd = new MySqlCommand("select [*],[column, column...] from User " + "WHERE Email=@email " + "AND Password=@password",
MySqlConn.conn);
答案 1 :(得分:1)
好吧,看起来你错过了查询中的SELECT
子句,除非它是如下所示的拼写错误
cmd = new MySqlCommand(" from User " + "WHERE Email=@email " + "
^... Here