Question

我想要一个带有字符串参数（数据）的函数，并将该字符串分解为单词（word）。之后，它应该获取目录中的所有文件，获取每个文件名并检查文件名中是否存在所有单词。如果存在，则打印文件的名称并打印“是否要打开它”，如果是，则打印“打开”并打破所有循环。如果不是那么它应该继续搜索。

最后，它应该打印文件是否存在于目录中。

这是我写的代码。

def file_search(data):
  data = data.split()

  for root, dirs, files in os.walk("/media/", topdown=False):
       word_match = True
       opened = False

       if not opened:

            for name in files:
                for word in data:
                    if word not in name:
                        word_match = False

                if word_match:
                    print "file found:" + name + "where path is" + root
                    print "do you want to open it "
                    answer = raw_input()
                    if answer == "yes" :
                        opened = True
                        print "file opened"
                        break

Answer 1

不知怎的，我修好了。

def file_search2(name, name_words):
check = True
for word in name_words:
    if word not in name:
        check = False
        break

return check




def file_search(filename):
    file_found = False
    file_opened = False
    words = filename.split()

    for root, dirs, files in os.walk('/media/', topdown=False):

        for name in files:



            if file_search2(name, words) and file_opened == False:
                file_found = True
                print "file found :" + name
                print "Do you want to open the file:"
                answer = raw_input()
                if "yes" in answer:
                    file_opened = True
                    print "file opened successfully"

    if file_opened == False:
        print "file not found"



file_search("file name with space")

在python中搜索文件

1 个答案: