Question

到目前为止：我正在进行preg_match_all搜索，我的输出是：Donald，Daisy，Huey，Dewey和Louie

代码是这样的：

$duckburg = array();
preg_match_all($pattern,$subject,$match);
$duckburg['residents'] = $match[1];
print_r($duckburg['residents']);

输出：

Array ( [residents] => Array ( [0] => Donald [1] => Daisy [2] => Huey [3] => Dewey [4] => Louie )

我的问题：我想在每个字符串中添加“Duck”

使用此帮助字符串：$lastname = " Duck"

输出应为：

Array ( [residents] => Array ( [0] => Donald Duck [1] => Daisy Duck [2] => Huey Duck [3] => Dewey Duck [4] => Louie Duck )

我尝试过（但它不起作用）：

preg_match_all($pattern,$subject,$match);
$matchy = $match.$lastname;
$duckburg['residents'] = $matchy[1];
print_r($duckburg['residents']);

是否可以在匹配字符串进入数组之前更改它？谢谢你的帮助！

Answer 1

迭代数组是一种可能的选择：

$lastname = " Duck";
preg_match_all($pattern,$subject,$matches);
foreach($matches as $key => $val){
    $duckburg['residents'][$key] = $val . $lastname;
}
print_r($duckburg['residents']);

Answer 2

Array_map是这种操纵的工具：

$match = Array ( 'residents' => Array ('Donald','Daisy','Huey','Dewey','Louie'));
$duckburg['residents'] = array_map(function($n) { return "$n Duck"; }, $match['residents']);
var_dump($duckburg);

<强>输出：

array(1) {
  ["residents"]=>
  array(5) {
    [0]=>
    string(11) "Donald Duck"
    [1]=>
    string(10) "Daisy Duck"
    [2]=>
    string(9) "Huey Duck"
    [3]=>
    string(10) "Dewey Duck"
    [4]=>
    string(10) "Louie Duck"
  }
}

preg_match_all：更改字符串$ match

2 个答案: