Question

在一个名为batches的应用程序中，我设置了不同的url模式。我现在有3个批量，个人和商业名称的网址。似乎在goind到最后2时我只是一直在看批量信息。在我的app-batch中，我有3个表/类。

请参阅我的网站网址模式：

urlpatterns = [
    url(r'^admin/', admin.site.urls),
    url(r'^batches/', include('batches.urls')),
    url(r'^screenings/', include('screenings.urls')),
    url(r'^individuals/', include('batches.urls')),
    url(r'^businessnames', include('batches.urls')),
]

这就是我的观点：

from __future__ import unicode_literals
from .models import BusinessName
from .models import Individuals
from .models import Batches

from django.shortcuts import render
from django.http import HttpResponse

# Create your views here.
def index(request):
    all_Batches = Batches.objects.all()
    html = ''
    for batch in all_Batches:
        url = '/batches/' + str(batch.id) + '/'
        html += '<a href="#"' + url + '">' + str(batch.FileName)+ '</a><br>'
    return  HttpResponse(html)

def detail(request, batches_id):  #parametrul asta batches_id tr sa se gaseasca in urls.py din app
    return HttpResponse("<h2>Details for Batches ID:"  + str(batches_id) + "</h2")


def index_businessname(request):
    all_BusinessNames = BusinessName.objects.all()
    html1 = ''
    for bn in all_BusinessNames:
        url = '/businessnames/' + str(bn.id) + '/'
        html1 += '<a href="#"' + url + '">' + bn.FullName + '</a><br>'
    return HttpResponse(html1)

def detail_businessname(request, businessname_id):
    return HttpResponse("<h2>Details for Business Names ID:"  + str(businessname_id) + "</h2")

def index_individual(request):
    all_individuals = Individuals.objects.all()
    html2 = ''
    for i in all_individuals:
        url = '/individuals/' + i.id + '/'
        html2 += '<a href="#"' + url + '">' + i.FullName + '</a><br>'
    return HttpResponse(html2)


def detail_individual(request, individuals_id):
    return HttpResponse("<h2>Details for Individual Names ID:"  + str(individuals_id)+ "</h2")

这就是我在我的应用网址中的内容：

urlpatterns = [
    # /batches/
    url(r'^$', views.index, name='index'),
    # /batches/2
    url(r'^(?P<batches_id>[0-9]+)/$',views.detail, name="detail"),

    # businessname/1
    url(r'^$',views.index_businessname, name="index_businessname"),
    # businessname/1
    url(r'^(?P<businessname_id>[0-9]+)/$', views.detail_businessname, name="detail_businessname"),


    # individuals/1
    url(r'^$', views.index_individual, name="index_individuals"),
    # individuals/1
    url(r'^(?P<individuals_id>[0-9]+)/$', views.detail_individual, name="detail_individual"),
]

如果有人可以帮助我，我会欠你很多。我阅读了文档，但我被困在其中。

谢谢你，科恩

Answer 1

问题是您要为同一个网址定义三个端点。 Django从上到下搜索模式并返回首先匹配的模式。因此，除非您明确说明，否则它不知道您指定了哪一个。因此，最好在相同的应用程序本身中为应用程序中的URL定义端点的前缀。

您可以在主urls.py，

中定义这样的端点

url(r'^batches/', include('batches.urls')),

然后，在app.urls.py相应地更改它们，

urlpatterns = [
    url(r'^$', views.index, name='index'),
    url(r'^/(?P<batches_id>[0-9]+)/$',views.detail, name="detail"),
    url(r'^businessname/$',views.index_businessname, name="index_businessname"),
    url(r'^businessname/(?P<businessname_id>[0-9]+)/$', views.detail_businessname, name="detail_businessname"),
    url(r'^individuals/$', views.index_individual, name="index_individuals"),
    url(r'^individuals/(?P<individuals_id>[0-9]+)/$', views.detail_individual, name="detail_individual"),
]

Django Views ---无法正确查看URL

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