Question

我坚持这个问题：各位大家好（不知道为什么它没出现在第一行......）

我有两张桌子：

-factures (invoices)
-commandes_clients (orders)

每个表都包含唯一的id_client。

我试图根据发票金额对每个客户的平均金额排序进行排序:(每个客户的总发票金额/同一客户的订单数量）

Client 1 Average order amount 1254.21
Client 2 Average order amount 951.88
Client 3 Average order amount 891.11
...

我想按平均金额排序以获得客户的掌声

Table facture contains :
id_client, invoice_number, total amount
Table commandes_clients contains :
id_client

感谢您的帮助

Answer 1

SELECT id_client,sum(total_amount)/count(invoice_number) as avg 
FROM factures group by id_client order by avg;

或者：

 SELECT id_client,sum(total_amount)/count(CC.id) as avg 
    FROM factures FA
    INNER JOIN commandes_clients CC ON FA.id_client=CC.id_client
    group by FA.id_client order by avg;

尝试以上查询。

在SQL SELECT中操作算术运算

1 个答案: