我有一个Lambda函数,它假设采用3个参数
public async Task<string> FunctionHandler(string pName, string dictName, ILambdaContext context)
{
//code...
}
答案 0 :(得分:6)
就个人而言,我没有在Lambda入口点试验过异步任务,因此无法对此发表评论。
然而,另一种方法是将Lambda函数入口点更改为:
public async Task<string> FunctionHandler(JObject input, ILambdaContext context)
然后将两个变量拉出来:
string dictName = input["dictName"].ToString();
string pName = input["pName"].ToString();
然后在AWS Web Console中输入:
{
"dictName":"hello",
"pName":"kitty"
}
或者可以使用JObject值并使用它,如以下示例代码所示:
using System;
using Microsoft.VisualStudio.TestTools.UnitTesting;
using Newtonsoft.Json.Linq;
using Newtonsoft.Json;
namespace SimpleJsonTest
{
[TestClass]
public class JsonObjectTests
{
[TestMethod]
public void ForgiveThisRunOnJsonTestJustShakeYourHeadSayUgghhhAndMoveOn()
{
//Need better names than dictName and pName. Kept it as it is a good approximation of software potty talk.
string json = "{\"dictName\":\"hello\",\"pName\":\"kitty\"}";
JObject jsonObject = JObject.Parse(json);
//Example Zero
string dictName = jsonObject["dictName"].ToString();
string pName = jsonObject["pName"].ToString();
Assert.AreEqual("hello", dictName);
Assert.AreEqual("kitty", pName);
//Example One
MeaningfulName exampleOne = jsonObject.ToObject<MeaningfulName>();
Assert.AreEqual("hello", exampleOne.DictName);
Assert.AreEqual("kitty", exampleOne.PName);
//Example Two (or could just pass in json from above)
MeaningfulName exampleTwo = JsonConvert.DeserializeObject<MeaningfulName>(jsonObject.ToString());
Assert.AreEqual("hello", exampleTwo.DictName);
Assert.AreEqual("kitty", exampleTwo.PName);
}
}
public class MeaningfulName
{
public string PName { get; set; }
[JsonProperty("dictName")] //Change this to suit your needs, or leave it off
public string DictName { get; set; }
}
}
重点是我不知道您是否可以在AWS Lambda中拥有两个输入变量。赔率是你不能。除此之外,如果你坚持使用json字符串或对象传递一个需要的多个变量,这可能是最好的。