Question

我遇到以下代码问题：

Query q =session.createQuery("select u from User u where u.location=? and u.id in (:user_ids)");
    q.setParameter(0, location);
    q.setParameterList("user_ids", userIds);
    return q.list();

返回：

$invoice_customers = [];
foreach ($new['data'] as $key=>$display) {

if ($display['customer'] == $customer){
    $invoice_customers[$key]['customer'] = $display['source']['customer'];
    $invoice_customers[$key]['name'] = $display['source']['name'];
    $invoice_customers[$key]['amount'] = $display['amount'];
    $invoice_customers[$key]['refunded'] = $display['refunded'];
    $invoice_customers[$key]['last4'] = $display['source']['last4'];
    $invoice_customers[$key]['id'] = $display['id'];
    $invoice_customers[$key]['created'] = $display['created'];
}
}

echo json_encode($invoice_customers);

正如你所看到的，我的主阵列中有一些数组。我想知道如何只访问主数组中的数组？ IE：像这样：

 {"3":
    {"customer":"xxxxx","name":"Testtt Test","amount":100,"refunded":false,"last4":"4242","id":"x","created":1500342123},
 "4xxx":
    {"customer":"xxxxx","name":"Testtt Test","amount":100,"refunded":false,"last4":"4242","id":"xxxx","created":1500340979}}

Answer 1

您现有的对象

var myobject ={
   "3":{
      "customer":"xxxxx",
      "name":"Testtt Test",
      "amount":100,
      "refunded":false,
      "last4":"4242",
      "id":"x",
      "created":1500342123
   },
   "4xxx":{
      "customer":"xxxxx",
      "name":"Testtt Test",
      "amount":100,
      "refunded":false,
      "last4":"4242",
      "id":"xxxx",
      "created":1500340979
   }
}

可以像myobject['3'], myobject['4xxx']

一样访问

如果要创建数组

，请使用下面的一个

json_encode(array_values($invoice_customers));

将生成，并且可以使用索引0,1....进行访问，如myarray[0], myarray[1] ...

var myarray =[
   {
      "customer":"xxxxx",
      "name":"Testtt Test",
      "amount":100,
      "refunded":false,
      "last4":"xxxx",
      "id":"x",
      "created":1500342123
   },
   {
      "customer":"xxxxx",
      "name":"Testtt Test",
      "amount":100,
      "refunded":false,
      "last4":"xxxx",
      "id":"xxxx",
      "created":1500340979
   }
]

以下是演示

var myobject ={
   "3":{
      "customer":"xxxxx",
      "name":"Testtt Test",
      "amount":100,
      "refunded":false,
      "last4":"4242",
      "id":"x",
      "created":1500342123
   },
   "4xxx":{
      "customer":"xxxxx",
      "name":"Testtt Test",
      "amount":100,
      "refunded":false,
      "last4":"4242",
      "id":"xxxx",
      "created":1500340979
   }
};
var myarray =[
   {
      "customer":"xxxxx",
      "name":"Testtt Test",
      "amount":100,
      "refunded":false,
      "last4":"xxxx",
      "id":"x",
      "created":1500342123
   },
   {
      "customer":"xxxxx",
      "name":"Testtt Test",
      "amount":100,
      "refunded":false,
      "last4":"xxxx",
      "id":"xxxx",
      "created":1500340979
   }
];

// access object
console.log(myobject['3']['customer']);
console.log(myobject['3'].name);

// access array
console.log(myarray[0]['customer']);
console.log(myarray[0].name);

PHP - 如何在JSON数组中迭代JSON数组

1 个答案: