我有一个名为path的对象:
var path = { "firstFloor": ["roomA1", "roomA6", "roomA5", "roomA2", "roomA3", "roomA4", "roomA10"],
"secondFloor": ["roomB4", "roomB5", "roomB6"],
"basementFloor": []}
现在我正常选择数组(path.firstFloor等),但是我需要在一个以键为参数的函数中选择这些对,所以:
function draw(floor) { //later on I will call this function with parameter firstFloor
$(path.floor).each(function(i, val){ //this is where I need to select.
var roomIdPath = path.firstFloor[i]
//console.log(roomIdPath);
var points = d3.select('#'+roomIdPath).attr('points').split(",");
var midX = (Number(points[0]) + Number(points[6])) / 2;
var midY = (Number(points[1]) + Number(points[3])) / 2;
floorArray.push({"x": midX, "y": midY});
});
}
不确定我是否清楚,基本上,我只需要在jQuery选择器中使用函数参数。反正有吗?
答案 0 :(得分:2)
如果要发送功能键,可以使用键访问映射到对象路径中键的值。
目前您使用过path.floor
,这是错误的,因为它会在您需要使用path[floor]
的路径对象中查找名为floor的键。你可以这样做:
function draw(floor) { //later on I will call this function with parameter firstFloor
$(path[floor]).each(function(i, val){ //this is where I need to select.
var roomIdPath = path[floor][i];
//console.log(roomIdPath);
var points = d3.select('#'+roomIdPath).attr('points').split(",");
var midX = (Number(points[0]) + Number(points[6])) / 2;
var midY = (Number(points[1]) + Number(points[3])) / 2;
floorArray.push({"x": midX, "y": midY});
});
}
答案 1 :(得分:0)
尝试使用括号表示法console.log(variable)
,参数将是一个值而不是变量,并且不要忘记偶尔使用SKView.allowsTransparency
进行调试
答案 2 :(得分:0)
不确定我的问题是否正确: 您可以迭代元素的键(注意地板可能是原型中具有其他属性的对象):
for(floor in floors){
//do your thing
}
使用Jquery 或更好:
$.each(floors, function(key, value){
//do the thing you were doing in the question
//key is your floor name, value is your array of rooms
});