我试图读取非均匀线ascii数据，例如
4 0.0790926412 -0.199457773 0.325952223 0.924105917 48915.3072 -2086.17061
73540.4807 10
4 0.0245689377 -0.805261448 -0.152373497 0.573006386 -39801.696 49084.2418
16665.3857 10
4 0.0427767979 -0.0185129676 -0.143135691 -0.989529911 38770.6518
-70784.7024 32640.6307 10
4 0.0262684678 0.137741 -0.820259709 -0.555158921 25293.3918 -51148.4003
-126522.859 10
4 0.145932295 0.466618154 -0.00805648931 -0.88442218 90951.8483 19221.4234
-40205.3438 10
4 0.0907820906 0.584060054 -0.671576188 0.455915866 -78193.2124 -31269.5848
47260.338 10
4 0.0794897928 0.654042761 0.537625452 0.532153117 24643.9195 39614.3788
97184.4856 10
4 0.0896920622 -0.517384933 -0.609729743 -0.600451889 -17455.9074 -17601.0439
-13991.5163 10
4 0.0295554749 -0.53757783 -0.3710939 0.757165368 20106.124 -171013.738
-14052.1145 10
4 0.0189505245 -0.773354757 -0.0747623556 -0.629549847 -71468.2726
-53145.1259 36948.4058 10
问题是我需要将每两行读成一行。我正在尝试使用pandas.read_csv或numpy.genfromtxt，但他们会阅读并分成独立的行。我尝试合并每两行没有成功，因为，你怎么看，有时我有一个分为7和2列的行，6和3列的somentimes。总共有9列要读。
答案 0 :(得分：1)
这样的事情应该有效。
将数据放入字符串或文档中，然后使用python进行操作。然后，当您拥有您想要的数据时，就可以使用pandas。
string1 = '''4 0.0790926412 -0.199457773 0.325952223 0.924105917 48915.3072 -2086.17061
73540.4807 10
4 0.0245689377 -0.805261448 -0.152373497 0.573006386 -39801.696 49084.2418
16665.3857 10
4 0.0427767979 -0.0185129676 -0.143135691 -0.989529911 38770.6518
-70784.7024 32640.6307 10
4 0.0262684678 0.137741 -0.820259709 -0.555158921 25293.3918 -51148.4003
-126522.859 10
4 0.145932295 0.466618154 -0.00805648931 -0.88442218 90951.8483 19221.4234
-40205.3438 10
4 0.0907820906 0.584060054 -0.671576188 0.455915866 -78193.2124 -31269.5848
47260.338 10
4 0.0794897928 0.654042761 0.537625452 0.532153117 24643.9195 39614.3788
97184.4856 10
4 0.0896920622 -0.517384933 -0.609729743 -0.600451889 -17455.9074 -17601.0439
-13991.5163 10
4 0.0295554749 -0.53757783 -0.3710939 0.757165368 20106.124 -171013.738
-14052.1145 10
4 0.0189505245 -0.773354757 -0.0747623556 -0.629549847 -71468.2726
-53145.1259 36948.4058 10'''
splitted = string1.splitlines()
result = ""
for index,item in enumerate(splitted):
if index % 2 != 0:
result += item+ "\n"
else:
result += item
print(result)
4 0.0790926412 -0.199457773 0.325952223 0.924105917 48915.3072 -2086.17061 73540.4807 10
4 0.0245689377 -0.805261448 -0.152373497 0.573006386 -39801.696 49084.2418 16665.3857 10
4 0.0427767979 -0.0185129676 -0.143135691 -0.989529911 38770.6518 -70784.7024 32640.6307 10
4 0.0262684678 0.137741 -0.820259709 -0.555158921 25293.3918 -51148.4003 -126522.859 10
4 0.145932295 0.466618154 -0.00805648931 -0.88442218 90951.8483 19221.4234 -40205.3438 10
4 0.0907820906 0.584060054 -0.671576188 0.455915866 -78193.2124 -31269.5848 47260.338 10
4 0.0794897928 0.654042761 0.537625452 0.532153117 24643.9195 39614.3788 97184.4856 10
4 0.0896920622 -0.517384933 -0.609729743 -0.600451889 -17455.9074 -17601.0439 -13991.5163 10
4 0.0295554749 -0.53757783 -0.3710939 0.757165368 20106.124 -171013.738 -14052.1145 10
或者如果您从文件中读取它：
data = open('/path/original.txt', 'r')
string1 = data.read()
splitted = string1.splitlines()
result = ""
for index,item in enumerate(splitted):
if index % 2 != 0:
result += item+ "\n"
else:
result += item
new_data = open('/path/new_data.txt','w')
new_data.write(result)
答案 1 :(得分：1)
如果我，我想以这种方式这样做：
import re
with open('data.txt') as f:
s = f.read().strip()
L = [float(i) for i in re.split(r'\s+', s)]
LL = [L[i:i+9] for i in range(0, len(L), 9)]
print(LL)
[[4.0,0.0790926412，-0.199457773,0.325952223,0.924105917,48915.3072，-2086.17061,73540.4807,10.0]，[4.0,0.0245689377，-0.805261448，-0.152373497,0.573006386，-39801.696,49084.2418,16665.3857,10.0]，[ 4.0,0.0427767979，-0.0185129676，-0.143135691，-0.989529911,38770.6518，-70784.7024,32640.6307,10.0]，[4.0,0.0262684678,0.137741，-0.820259709，-0.555158921,2529.3918，-51148.4003，-126522.859,10.0]，[4.0， 0.145932295,0.466618154，-0.00805648931，-0.88442218,90951.8483,19221.4234，-40205.3438,10.0]，[4.0,0.0907820906,0.584060054，-0.671576188,0.455915866，-78193.2124，-31269.5848,47260.338,10.0]，[4.0,0.0794897928,0.654042761， 0.537625452,0.532153117,24643.9195,39614.3788,97184.4856,10.0]，[4.0,0.0896920622，-0.517384933，-0.609729743，-0.600451889，-17455.9074，-17601.0439，-13991.5163,10.0]，[4.0,0.0295554749，-0.53757783，-0.3710939， 0.757165368,20106.124，-171013.738，-14052.1145,10.0]，[4.0,0.0189505245，-0.773354757，-0.0747623556，-0.62954 9847，-71468.2726，-53145.1259,36948.4058,10.0]]
答案 2 :(得分：1)
或者像这样，因为你知道每个案例有两行。
每次循环读取两行输入。当第一行为空时，这意味着输入文件中没有更多行可用。每次读取一对行时，它们首先丢弃从第一行开始的行。
Pandas可以读取使用空格代替逗号的'csv'文件。
>>> import pandas as pd
>>> with open('temp.txt') as input, open('temp.csv', 'w') as the_csv:
... while True:
... first = input.readline()
... if not first:
... break
... second = input.readline()
... r = the_csv.write(first.strip()+second)
...
>>> df = pd.read_csv('temp.csv', sep='\s+')
>>> df
4 0.0790926412 -0.199457773 0.325952223 0.924105917 48915.3072 \
0 4 0.024569 -0.805261 -0.152373 0.573006 -39801.6960
1 4 0.042777 -0.018513 -0.143136 -0.989530 38770.6518
2 4 0.026268 0.137741 -0.820260 -0.555159 25293.3918
3 4 0.145932 0.466618 -0.008056 -0.884422 90951.8483
4 4 0.090782 0.584060 -0.671576 0.455916 -78193.2124
5 4 0.079490 0.654043 0.537625 0.532153 24643.9195
6 4 0.089692 -0.517385 -0.609730 -0.600452 -17455.9074
7 4 0.029555 -0.537578 -0.371094 0.757165 20106.1240
8 4 0.018951 -0.773355 -0.074762 -0.629550 -71468.2726
-2086.17061 73540.4807 10
0 49084.2418 16665.3857 10
1 -70784.7024 32640.6307 10
2 -51148.4003 -126522.8590 10
3 19221.4234 -40205.3438 10
4 -31269.5848 47260.3380 10
5 39614.3788 97184.4856 10
6 -17601.0439 -13991.5163 10
7 -171013.7380 -14052.1145 10
8 -53145.1259 36948.4058 10