Question

我正在分析日志文件，我希望通过降序排序请求，使其更容易阅读。问题是我有一个二维数组，每个都有一个对象，我想通过它们的一个对象属性（这里的平均响应时间）对数组进行排序，我不知道如何访问它......

以下是最终日志文件的一部分供您理解：

[
    [
        {
            "Request": "/sql/sqlweb/",
            "Average response time": "2.685 ms",
            "Number of calls": 1
        }
    ],
    [
        {
            "Request": "/",
            "Average response time": "1.219 ms",
            "Number of calls": 2529
        }
    ],
    [
        {
            "Request": "/mysql/admin/",
            "Average response time": "4.086 ms",
            "Number of calls": 1
        }
    ],
    [
        {
            "Request": "/mysql/sqlmanager/",
            "Average response time": "2.774 ms",
            "Number of calls": 1
        }
    ],
    [
        {
            "Request": "/phpmyadmin/",
            "Average response time": "2.417 ms",
            "Number of calls": 2
        }
    ]
]

这是在我的数组上的JSON.stringify（）之后。如果需要，我也可以复制/粘贴当前版本的代码。

Ps：如果有帮助，我可以轻松删除“ms”。

Answer 1

您可以使用sort()，您可以编写一个比较器函数，在该函数中使用平均响应时间比较数组内的对象，为此您可以使用parseFloat()

var arr = [
[
    {
        "Request": "/sql/sqlweb/",
        "Average response time": "2.685 ms",
        "Number of calls": 1
    }
],
[
    {
        "Request": "/",
        "Average response time": "1.219 ms",
        "Number of calls": 2529
    }
],
[
    {
        "Request": "/mysql/admin/",
        "Average response time": "4.086 ms",
        "Number of calls": 1
    }
],
[
    {
        "Request": "/mysql/sqlmanager/",
        "Average response time": "2.774 ms",
        "Number of calls": 1
    }
],
[
    {
        "Request": "/phpmyadmin/",
        "Average response time": "2.417 ms",
        "Number of calls": 2
    }
]
];

arr.sort(function(a,b){
return parseFloat(a[0]["Average response time"]) - parseFloat(b[0]["Average response time"]);
});

console.log(arr);

Answer 2

你可以获取内部数组的第一个对象，然后获取想要的属性进行排序。

＆＃13;

var array = [[{ Request: "/sql/sqlweb/", "Average response time": "2.685 ms", "Number of calls": 1 }], [{ Request: "/", "Average response time": "1.219 ms", "Number of calls": 2529 }], [{ Request: "/mysql/admin/", "Average response time": "4.086 ms", "Number of calls": 1 }], [{ Request: "/mysql/sqlmanager/", "Average response time": "2.774 ms", "Number of calls": 1 }], [{ Request: "/phpmyadmin/", "Average response time": "2.417 ms", "Number of calls": 2 }]];

array.sort(function (a, b) {
    function getV(o) {
        return o[0]['Average response time'].match(/\d+\.?\d*/);
    }
    return getV(b) - getV(a);
});

console.log(array);

＆＃13;

.as-console-wrapper { max-height: 100% !important; top: 0; }

＆＃13;

Answer 3

你可以这样做：

[
    [
        {
            "Request": "/sql/sqlweb/",
            "Average response time": "2.685 ms",
            "Number of calls": 1
        }
    ],
    [
        {
            "Request": "/",
            "Average response time": "1.219 ms",
            "Number of calls": 2529
        }
    ],
    [
        {
            "Request": "/mysql/admin/",
            "Average response time": "4.086 ms",
            "Number of calls": 1
        }
    ],
    [
        {
            "Request": "/mysql/sqlmanager/",
            "Average response time": "2.774 ms",
            "Number of calls": 1
        }
    ],
    [
        {
            "Request": "/phpmyadmin/",
            "Average response time": "2.417 ms",
            "Number of calls": 2
        }
    ]
].sort(function(a, b) {
    return Number(a[0]["Average response time"].replace(/[^0-9]+/g, "")) - Number(b[0]["Average response time"].replace(/[^0-9]+/g, ""));
});

Answer 4

您需要将array.sort与自定义比较器一起使用。

在Javascript / Node.Js中按二维数组中的对象属性排序

4 个答案: