从列表中删除字符

Question

您好我有一个列表，列表中的每个项目在开头都有相同的字符。如何删除这些字符。 ＆＃34; SITENAME ........................................＆＃34; < / p>

我试过使用result.split（）它会抛出一个错误。这是我到目前为止的代码和

下面的输出

createlist = open('ztest12.txt', 'r')
result = [line.split(',') for line in createlist.readlines()]
print result




[['Site Name........................................ Denver\n'], 
['Site Name........................................ DenverOutdoor\n'], 
['Site Name........................................ Dietzenbach\n'], 
['Site Name........................................ EG3\n'], 
['Site Name........................................ Edina\n'], 
['Site Name........................................ Hongkong\n'], 
['Site Name........................................ Honolulu\n'], 
['Site Name........................................ HooneePlace\n'], 
['Site Name........................................ Juarez\n'], 
['Site Name........................................ KansasCity\n'], 
['Site Name........................................ Kent\n'], 
['Site Name........................................ LA\n'], 
['Site Name........................................ Lanham\n'], 
['Site Name........................................ Lebanon\n'], 
['Site Name........................................ Lockbourne\n'], 
['Site Name........................................ London\n'], 
['Site Name........................................ Mesa\n'], 
['Site Name........................................ Minneapolis\n'], 
['Site Name........................................ NewMexico\n'], 
['Site Name........................................ NewYork']]

Answer 1

将它们分开：

with open('ztest12.txt', 'r') as f:
    result = [line[50:].rstrip() for line in f]

Answer 2

我看到两个选项：

• 清理一个：使用正则表达式

• 快速而肮脏的一个：

  clean = line [50：]＃保留第50个

之后的所有字符

Answer 3

使用＆＃34;切片＆＃34;概念：

>>> x = "Hello World!"

>>> x[2:]

'llo World!'

>>> x[:2]

'He'

希望它有所帮助。

Answer 4

您尝试在逗号上拆分字符串，但其中包含 no 逗号。无论如何，这是replace的工作，而不是split：

createlist = open('ztest12.txt', 'r')
result = [ line.replace('Site Name........................................ ', '') for line in createlist ]

Answer 5

您可以使用str.rsplit()来完成此任务：

>>> data = [['Site Name........................................ Denver\n'], 
['Site Name........................................ DenverOutdoor\n'], 
['Site Name........................................ Dietzenbach\n'], 
['Site Name........................................ EG3\n'], 
['Site Name........................................ Edina\n'], 
['Site Name........................................ Hongkong\n'], 
['Site Name........................................ Honolulu\n'], 
['Site Name........................................ HooneePlace\n'], 
['Site Name........................................ Juarez\n'], 
['Site Name........................................ KansasCity\n'], 
['Site Name........................................ Kent\n'], 
['Site Name........................................ LA\n'], 
['Site Name........................................ Lanham\n'], 
['Site Name........................................ Lebanon\n'], 
['Site Name........................................ Lockbourne\n'], 
['Site Name........................................ London\n'], 
['Site Name........................................ Mesa\n'], 
['Site Name........................................ Minneapolis\n'], 
['Site Name........................................ NewMexico\n'], 
['Site Name........................................ NewYork']]
>>> 
>>> [[s[0].rsplit('.')[-1]] for s in data]
[[' Denver\n'],
 [' DenverOutdoor\n'],
 [' Dietzenbach\n'],
 [' EG3\n'],
 [' Edina\n'],
 [' Hongkong\n'],
 [' Honolulu\n'],
 [' HooneePlace\n'],
 [' Juarez\n'],
 [' KansasCity\n'],
 [' Kent\n'],
 [' LA\n'],
 [' Lanham\n'],
 [' Lebanon\n'],
 [' Lockbourne\n'],
 [' London\n'],
 [' Mesa\n'],
 [' Minneapolis\n'],
 [' NewMexico\n'],
 [' NewYork']]
>>> 

然而，也许更强大的解决方案是使用re.sub()：

>>> from re import sub
>>> 
>>> [[sub('Site Name\.*', '', s[0])] for s in data]
[[' Denver\n'],
 [' DenverOutdoor\n'],
 [' Dietzenbach\n'],
 [' EG3\n'],
 [' Edina\n'],
 [' Hongkong\n'],
 [' Honolulu\n'],
 [' HooneePlace\n'],
 [' Juarez\n'],
 [' KansasCity\n'],
 [' Kent\n'],
 [' LA\n'],
 [' Lanham\n'],
 [' Lebanon\n'],
 [' Lockbourne\n'],
 [' London\n'],
 [' Mesa\n'],
 [' Minneapolis\n'],
 [' NewMexico\n'],
 [' NewYork']]
>>>