Question

尝试打开路径时出现此错误。它需要我的def中的PK并且我插入它，但问题仍然存在。如果有人可以提供帮助，我会欠你很多！

这是我在浏览器中遇到的错误：

TypeError at /batches/
index() missing 1 required positional argument: 'pk'
Request Method: GET
Request URL:    http://127.0.0.1:8000/batches/
Django Version: 1.11.1
Exception Type: TypeError
Exception Value:    
index() missing 1 required positional argument: 'pk'
Exception Location: /Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site-packages/django/core/handlers/base.py in _get_response, line 185
Python Executable:  /Library/Frameworks/Python.framework/Versions/3.6/bin/python3.6
Python Version: 3.6.1
Python Path:    
['/Users/cohen/Documents/project/sanctions',
 '/Users/cohen/Documents/project/sanctions',
 '/Library/Frameworks/Python.framework/Versions/3.6/lib/python36.zip',
 '/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6',
 '/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/lib-dynload',
 '/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site-packages',
 '/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site-packages/PyObjC']
Server time:    Mon, 24 Jul 2017 10:47:02 +0000

我的网址分批

from django.conf.urls import url
from . import views

urlpatterns = [
    # /batches/
    url(r'^$', views.index, name='index'),

    # /batches/2
    url(r'^(?P<batches_id>[0-9]+)/$',views.detail, name="detail"),

    # businessname/1
    url(r'^(?P<businessname_id>[0-9]+)/$',views.index_businessname, name="detail_businessname"),

    # individuals/1
    url(r'^(?P<individuals_id>[0-9]+)/$', views.index_individuals, name="detail_individuals"),
]

观点：

# -*- coding: utf-8 -*-
from __future__ import unicode_literals
from .models import BusinessName
from .models import Individuals
from .models import Batches

from django.shortcuts import render
from django.http import HttpResponse

# Create your views here.
def index(request, pk):
    all_Batches = Batches.objects.all()
    html = ''
    for batch in all_Batches:
        url = '/batches/' + str(batch.id) + '/'
        html += '<a href="#"' + url + '">' + str(batch.BatchNumber)+ '</a><br>'
    return  HttpResponse(html)

def detail(request, batch_id):
    return HttpResponse("<h2>Details for Batches ID:"  + str(batch_id) + "</h2")


def index_businessname(request):
    all_BusinessNames = BusinessName.objects.all()
    html = ''
    for bn in all_BusinessNames:
        url = '/businessname/' + str(bn.id) + '/'
        html += '<a href="#"' + url + '">' + bn.FullName + '</a><br>'
    return HttpResponse(html)

def detail_businessnames(request, bn_id):
    return HttpResponse("<h2>Details for Business Names ID:"  + str(bn_id) + "</h2")

def index_individuals(request):
    all_individuals = Individuals.objects.all()
    html = ''
    for i in all_individuals:
        url = '/individuals/' + str(i.id) + '/'
        html += '<a href="#"' + url + '">' + i.FullName + '</a><br>'
    return HttpResponse(html)


def detail_individuals(request, i_id):
    return HttpResponse("<h2>Details for Individual Names ID:"  + str(i_id)+ "</h2")

提前谢谢你，科恩

Answer 1

索引视图有两个参数。您编写的网址仅为request。您必须提供pk作为输入，就像detail网址

一样

Answer 2

在您的网址中加入pk。

像这样更改您的网址

url(r'(?P<pk>\d+)/$', views.index, name='index'),

代替，

# /batches/

url(r'^$', views.index, name='index'),

或

如果您没有将pk传递给观看广告，请从pk视图中移除index，如下所示。

def index(request): all_Batches = Batches.objects.all() html = '' for batch in all_Batches: url = '/batches/' + str(batch.id) + '/' html += '<a href="#"' + url + '">' + str(batch.BatchNumber)+ '</a><br>' return HttpResponse(html)

Answer 3

您的网址/批次/没有参数。所以，您的索引视图应为

def index(request):
   # ......

Django Error --- index（）缺少1个必需的位置参数：＆＃39; pk＆＃39;

3 个答案: