Question

我需要在特定的td中将多个sql查询插入一个表中。我怎么能这样做？我有这个查询，工作正常：

$sql = "SELECT Code, Name, Specification, Specification2, X_pozicane_u FROM StoreCards";
$stmt = sqlsrv_query( $conn, $sql );

并输出：

while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC) ) {
echo "<tr>";
echo "<td>" . $row['Code'] . "</td>";
echo "<td>" . $row['Name'] . "</td>";
echo "<td>" . $row['Specification'] . "</td>";
echo "<td>" . $row['Specification2'] . "</td>";
echo "<td>" . $row['X_pozicane_u'] . "</td>";
echo "</tr>";

如何设置sql2并将其插入特定的TD？

谢谢

Answer 1

试试这个：

<?php
$sql  = "SELECT Code, Name, Specification, Specification2, X_pozicane_u FROM StoreCards";
$stmt = $conn->query($sql);
while ($row = $result->fetch_assoc()) {
    echo "<tr>";
    echo "<td>" . $row['Code'] . "</td>";
    echo "<td>" . $row['Name'] . "</td>";
    echo "<td>" . $row['Specification'] . "</td>";
    echo "<td>" . $row['Specification2'] . "</td>";
    echo "<td>" . $row['X_pozicane_u'] . "</td>";
    echo "</tr>";
}
?>

php多个sql查询到一个表中

1 个答案: