Question

我在凭据正确时创建了一个登录表单，它将转到另一个页面，但它会显示一个空页面。

if(isset($_POST['login'])){
    $username = $_POST['username'];
    $password = $_POST['password'];

    $query = "SELECT username as username, password as password
                from tbl_users
                where user_type ='system admin'";
    $result= sqlsrv_query($db,$query);

    while ($user=sqlsrv_fetch_array($result, SQLSRV_FETCH_ASSOC)) {
        $uname = $user['username'];
        $pwd = $user['password'];
    }

        // $url = 'http://localhost/chart/e/home.php';
        if ($username == $uname && $password == $pwd ) {
            header('Location : http://localhost/chart/e/home.php');
            exit;
        }

        else{
            echo "<script> alert('error') </script>";
        }

}

这是表格

<form method="POST">
    <input type="text" class="text" placeholder ="username" name="username">
    <input type="password" placeholder ="password" name="password">
    <input type="submit" name="login" value="Sign in">
</form>

Answer 1

删除标题字段（Location）和冒号（:）之间的空格：

header('Location: http://localhost/chart/e/home.php');

每个标题字段由名称后跟冒号（“：”）和字段值组成。字段名称不区分大小写。字段值可以在任何数量的LWS之前，但优选单个SP。

供参考，见：

http://www.faqs.org/rfcs/rfc2616.html

Answer 2

if（（$ username == $ uname）＆amp;＆amp;（$ password == $ pwd））{$ url =“http://localhost/chart/e/home.php”; 标题（'Location：'。$ url）;退出; }

标头位置在if语句

2 个答案: