如果sum或count在列中没有值，则显示零

Question

这是我的查询运行查找总计。

我只是在这里混淆。请告诉我。

SELECT 
    CASE 
       WHEN SUBSTRING(FL.TRAN,1,2)='02' THEN 'TOTAL APPLES:'
       WHEN SUBSTRING(FL.TRAN,1,2)='01' THEN 'TOTAL BANANAS:'
       WHEN SUBSTRING(FL.TRAN,1,2)='40' THEN 'TOTAL ORANGES:'
       WHEN SUBSTRING(FL.TRAN,1,2)='31' THEN 'TOTAL GRAPES:'
    END TYPE,
    COUNT(FR.AMT) COUNT,
    ISNULL(SUM(FR.AMT),0) AMOUNT
FROM
    MYDB.FIN_FRUITLIST201706 AS FL 
JOIN 
    MYDB.FIN_FRUITRATE201706 AS FR ON FL.TSTAMP_TRANS = FR.TSTAMP_TRANS 
                                   AND FL.UNIQUENESS_KEY = FR.UNIQUENESS_KEY
WHERE 
    FL.TSTAMP_TRANS LIKE'201706%'
    AND SUBSTRING(FL.TRAN, 1, 2) IN ('02', '01', '40', '31')
GROUP BY
    CASE 
       WHEN SUBSTRING(FL.TRAN,1,2)='02' THEN 'TOTAL APPLES:'
       WHEN SUBSTRING(FL.TRAN,1,2)='01' THEN 'TOTAL BANANAS:'
       WHEN SUBSTRING(FL.TRAN,1,2)='40' THEN 'TOTAL ORANGES:'
       WHEN SUBSTRING(FL.TRAN,1,2)='31' THEN 'TOTAL GRAPES:'
    END

UNION ALL

SELECT 
    'GRAND TOTALS:' TYPE,
    COUNT(FR.AMT) COUNT,
    ISNULL(SUM(FR.AMT),0) AMOUNT
FROM
    MYDB.FIN_FRUITLIST201706 AS FL 
JOIN 
    MYDB.FIN_FRUITRATE201706 AS FR ON FL.TSTAMP_TRANS = FR.TSTAMP_TRANS 
                                   AND FL.UNIQUENESS_KEY = FR.UNIQUENESS_KEY
WHERE 
    FL.TSTAMP_TRANS LIKE'201706%'
    AND SUBSTRING(FL.TRAN, 1, 2) IN ('02', '01', '40', '31');

以下是输出的屏幕截图：

如果总数没有任何值，只需要在此处显示为零。

如果表中没有苹果，只想放零。

• TOTAL APPLES：0 0
• TOTAL BANANAS：3 6924
• TOTAL ORANGES：0 0
• TOTAL GRAPES：0 0

我只是在这里混淆。请告诉我。

Answer 1

请尝试此操作并检查结果。

SELECT 
    CASE 
       WHEN SUBSTRING(FL.TRAN,1,2)='02' THEN 'TOTAL APPLES:'
       WHEN SUBSTRING(FL.TRAN,1,2)='01' THEN 'TOTAL BANANAS:'
       WHEN SUBSTRING(FL.TRAN,1,2)='40' THEN 'TOTAL ORANGES:'
       WHEN SUBSTRING(FL.TRAN,1,2)='31' THEN 'TOTAL GRAPES:'
    END TYPE,
    COUNT(FR.AMT) COUNT,
    ISNULL(SUM(FR.AMT),0) AMOUNT
FROM
    MYDB.FIN_FRUITLIST201706 AS FL 
LEFT JOIN 
    MYDB.FIN_FRUITRATE201706 AS FR ON FL.TSTAMP_TRANS = FR.TSTAMP_TRANS 
                                   AND FL.UNIQUENESS_KEY = FR.UNIQUENESS_KEY
WHERE 
    FL.TSTAMP_TRANS LIKE'201706%'
    AND SUBSTRING(FL.TRAN, 1, 2) IN ('02', '01', '40', '31')
GROUP BY
    CASE 
       WHEN SUBSTRING(FL.TRAN,1,2)='02' THEN 'TOTAL APPLES:'
       WHEN SUBSTRING(FL.TRAN,1,2)='01' THEN 'TOTAL BANANAS:'
       WHEN SUBSTRING(FL.TRAN,1,2)='40' THEN 'TOTAL ORANGES:'
       WHEN SUBSTRING(FL.TRAN,1,2)='31' THEN 'TOTAL GRAPES:'
    END

UNION ALL

SELECT 
    'GRAND TOTALS:' TYPE,
    COUNT(FR.AMT) COUNT,
    ISNULL(SUM(FR.AMT),0) AMOUNT
FROM
    MYDB.FIN_FRUITLIST201706 AS FL 
JOIN 
    MYDB.FIN_FRUITRATE201706 AS FR ON FL.TSTAMP_TRANS = FR.TSTAMP_TRANS 
                                   AND FL.UNIQUENESS_KEY = FR.UNIQUENESS_KEY
WHERE 
    FL.TSTAMP_TRANS LIKE'201706%'
    AND SUBSTRING(FL.TRAN, 1, 2) IN ('02', '01', '40', '31');