Question

我试图解决这个问题。我创建了一个菜单和一个Scanner来获取变量。现在我希望每个对象都存储在一个包含自己信息的数组中。但是我的代码没有按照我想要的方式工作。

package com.Adams;
import java.util.Scanner;
public class Main {

    public static void main(String[] args) {

        Scanner vehicle = new Scanner(System.in);
        System.out.println("Enter your auctionId ");
        String auctionId = vehicle.nextLine() ;
        System.out.println("Enter the vehicule description");
        String vehicleDescription = vehicle.nextLine();
        System.out.println("What is the reserve price");
        int resevePrice = vehicle.nextInt();

        VehiculeAuction newVehicle = new VehiculeAuction(auctionId,      vehicleDescription, resevePrice );



        //  Define an array of VehicleAuction references named auctions,
        // which can be used to store up to 20 VehicleAuction objects.

        VehiculeAuction auctions[] = new VehiculeAuction[20];
        for (int i = 0; i < auctions.length; i ++) {
            auctions[i] = new VehiculeAuction("", "", 0);
            System.out.println(auctions[i]);
        }

        int auctionCount = 0;
        do {
            auctionCount++;

            System.out.printf("***** Auction System Menu *****");
            System.out.printf("%n" + "A. " + "Add New Vehicle Auction");
            System.out.printf("%n" + "B. " + "Display All Vehicle Auctions");
            System.out.printf("%n" + "C. " + "Submit Bid for Vehicle");
            System.out.printf("%n" + "D. " + "List Ended Vehicle Auctions");
            System.out.printf("%n" + "X. " + "Exit the program");
            System.out.printf("%n" + "Enter your selection: ");

            Scanner console = new Scanner(System.in);
            String selection = console.nextLine();

            switch (selection.toUpperCase()) {
                case "A": {
                    System.out.println("testA");
                    break;
                }
                case "B": {
                    System.out.println("testB");
                    //Display all vehicle auctions
                    break;
                }
                case "C": {
                    System.out.println("testC");
                    //Submit Bid for Vehicle
                    break;
                }
                case "D": {
                    System.out.println("testD");
                    //List ended vehicle auctions
                    break;
                }
                case "X": {
                    System.exit(0);
                }
                default:
                    System.out.printf("That is not a valid response. Try Again.");
            }
        } while (auctionCount <= 20);

        System.out.println(auctionCount);
    }
}

Answer 1

三个观察结果：

您在顶部有一段代码，要求提供拍卖ID和车辆信息。为什么会这样？它不应该是下面case "A":处理的一部分吗？
auctionCount++循环顶部的do...while行：为什么会出现？如果auctionCount确实是竞价计数，您只想在实际将竞价添加到您的列表时增加它，是吗？我认为这只应该作为case "A":处理的一部分而发生。事实上，auctionCount只是计算您要求用户输入菜单选项的次数。
Scanner上有多个System.in：您应该只创建一个并在每次需要输入时使用它。每个Scanner都希望它是仅一个读取输入，并且试图读取相同输入源的几个Scanner将相互“混淆”。

除了这些问题之外，看起来你有一个相当不错的开始。

将对象信息传递给数组Java

1 个答案: