如何使用distinct和order by在条件查询中从oracle中选择列。我能够使用不同的或有效的顺序，但不能同时使用它们。 我在标准中遇到的问题，对于一列是不同的，我必须根据同一个表中的另一列来排序结果。
Criteria cr = sessionFactory.getCurrentSession().createCriteria(example.class);
cr.add(Restrictions.eq("quote", quote));
cr.add(Restrictions.eq("optn", optn));
cr.add(Restrictions.eq("prdct",prod));
//Adding distinct to show only distinct messages,
ProjectionList projection = Projections.projectionList();
projection.add(Projections.distinct(Projections.property(("Message"))),"Message");
projection.add(Projections.property("screenNo"),"screenNo");
cr.setProjection(projection);
cr.addOrder(Order.asc("screenNo"));
cr.setResultTransformer(new AliasToBeanResultTransformer(example.class));
resultList=cr.list();
示例表
quote |S option |S message |S screenNo
1123 |S 11 |S This screen is about policy |S 100
2222 |S 22 |S This screen is about loss |S 103
3333 |S 33 |S This screen is about term |S 102
4444 |S 44 |S This screen is about policy |S 101