Question

我正在尝试使用Kotlin在我的Android应用中复制以下ListView：https://github.com/bidrohi/KotlinListView。

不幸的是我收到错误，我无法自行解决。这是我的代码：

MainActivity.kt:

override fun onCreate(savedInstanceState: Bundle?) {
    super.onCreate(savedInstanceState)
    setContentView(R.layout.activity_main)

    val listView = findViewById(R.id.list) as ListView
    listView.adapter = ListExampleAdapter(this)
}

private class ListExampleAdapter(context: Context) : BaseAdapter() {
    internal var sList = arrayOf("Eins", "Zwei", "Drei")
    private  val mInflator: LayoutInflater

    init {
        this.mInflator = LayoutInflater.from(context)
    }

    override fun getCount(): Int {
        return sList.size
    }

    override fun getItem(position: Int): Any {
        return sList[position]
    }

    override fun getItemId(position: Int): Long {
        return position.toLong()
    }

    override fun getView(position: Int, convertView: View?, parent: ViewGroup): View? {
        val view: View?
        val vh: ListRowHolder

        if(convertView == null) {
            view = this.mInflator.inflate(R.layout.list_row, parent, false)
            vh = ListRowHolder(view)
            view.tag = vh
        } else {
            view = convertView
            vh = view.tag as ListRowHolder
        }

        vh.label.text = sList[position]
        return view
    }
}

private class ListRowHolder(row: View?) {
    public val label: TextView

    init {
        this.label = row?.findViewById(R.id.label) as TextView
    }
}
}

布局与此处完全相同：https://github.com/bidrohi/KotlinListView/tree/master/app/src/main/res/layout

我收到的完整错误消息是： 错误：（92,31）类型推断失败：没有足够的信息来推断有趣的findViewById（p0：Int）中的参数T：T！请明确说明。

我很感激我能得到的任何帮助。

Answer 1

您必须使用API级别26（或更高级别）。此版本更改了View.findViewById()的签名 - 请参阅此处https://developer.android.com/preview/api-overview.html#fvbi-signature

因此，在您的情况下，findViewById的结果不明确，您需要提供类型：

1 /更改

val listView = findViewById(R.id.list) as ListView到

val listView = findViewById<ListView>(R.id.list)

2 /更改

this.label = row?.findViewById(R.id.label) as TextView到

this.label = row?.findViewById<TextView>(R.id.label) as TextView

请注意，在2 /中只需要强制转换，因为row可以为空。如果label 也可以为空，或者如果你使row不可为空，则不需要它。

Answer 2

Andoid O从

更改findViewById api

public View findViewById（int id）;

到

public final T findViewById（int id）

所以，如果你是API 26的目标，你可以改变

val listView = findViewById（R.id.list）作为ListView

到

val listView = findViewById（R.id.list）

或

val listView：ListView = findViewById（R.id.list）

Answer 3

正在运作

API等级25或以下使用此

    var et_user_name = findViewById(R.id.et_user_name) as EditText

API级别26或以上使用此

    val et_user_name: EditText = findViewById(R.id.et_user_name)

快乐的编码！

Answer 4

将您的代码更改为此。发生主要变化的地方标有星号。

package com.phenakit.tg.phenakit

import android.content.Context
import android.os.Bundle
import android.support.design.widget.BottomNavigationView
import android.support.v7.app.AppCompatActivity
import android.view.LayoutInflater
import android.view.View
import android.view.ViewGroup
import android.widget.BaseAdapter
import android.widget.ListView
import android.widget.TextView

public class MainActivity : AppCompatActivity() {

    private var mTextMessage: TextView? = null

    private val mOnNavigationItemSelectedListener = BottomNavigationView.OnNavigationItemSelectedListener { item ->
        when (item.itemId) {
            R.id.navigation_home -> {
                mTextMessage!!.setText(R.string.title_home)
                return@OnNavigationItemSelectedListener true
            }
            R.id.navigation_dashboard -> {
                mTextMessage!!.setText(R.string.title_dashboard)
                return@OnNavigationItemSelectedListener true
            }
            R.id.navigation_notifications -> {
                setContentView(R.layout.activity_list_view)
                return@OnNavigationItemSelectedListener true
            }
        }
        false
    }

    override fun onCreate(savedInstanceState: Bundle?) {
        super.onCreate(savedInstanceState)
        setContentView(R.layout.activity_main)

        mTextMessage = findViewById(R.id.message) as TextView?
        val navigation = findViewById(R.id.navigation) as BottomNavigationView
        navigation.setOnNavigationItemSelectedListener(mOnNavigationItemSelectedListener)


        **val listView = findViewById<ListView>(R.id.list)**



        **listView?.adapter = ListExampleAdapter(this)**
    }

    private class ListExampleAdapter(context: Context) : BaseAdapter() {
        internal var sList = arrayOf("Eins", "Zwei", "Drei")
        private  val mInflator: LayoutInflater

        init {
            this.mInflator = LayoutInflater.from(context)
        }

        override fun getCount(): Int {
            return sList.size
        }

        override fun getItem(position: Int): Any {
            return sList[position]
        }

        override fun getItemId(position: Int): Long {
            return position.toLong()
        }

        override fun getView(position: Int, convertView: View?, parent: ViewGroup): View? {
            val view: View?
            val vh: ListRowHolder

            if(convertView == null) {
                view = this.mInflator.inflate(R.layout.list_row, parent, false)
                vh = ListRowHolder(view)
                view.tag = vh
            } else {
                view = convertView
                vh = view.tag as ListRowHolder
            }

            vh.label.text = sList[position]
            return view
        }
    }

    private class ListRowHolder(row: View?) {
        public var label: TextView

        **init { this.label = row?.findViewById<TextView?>(R.id.label) as TextView }**
    }
}

Answer 5

我建议您使用synthetics kotlin Android扩展程序：

https://kotlinlang.org/docs/tutorials/android-plugin.html

https://antonioleiva.com/kotlin-android-extensions/

在您的情况下，代码将是这样的：

init {
   this.label = row.label
}

就这么简单;）

“没有足够的信息来推断参数T”与Kotlin和Android

5 个答案: