我使用ajax提交表单并将值插入数据库..我尝试了很多方法,但验证错误检查没有正确。 这是我的代码
$(document).ready(function() {
$('body').on('click', '#Submit', function(e) {
e.preventDefault();
var formData = new FormData($(this).parents('form')[0]);
$.ajax({
url: 'formrelay.php',
type: 'POST',
xhr: function() {
var myXhr = $.ajaxSettings.xhr();
return myXhr;
},
success: function(data) {
document.getElementById('Message').innerHTML = data;
},
data: formData,
cache: false,
contentType: false,
processData: false
});
return false;
});
});
我尝试使用submithandler(在其中一个教程中看到)但是它没有用..请帮助..下面的代码
$(document).ready(function(){
$("#relay_form").validate({
rules: {
f_name: { required : true }
},
submitHandler : function (form) {
e.preventDefault();
var formData = new FormData($(this).parents('form')[0]);
$.ajax({
url:'form_relay.php',
type: 'POST',
xhr: function() {
var myXhr = $.ajaxSettings.xhr();
return myXhr;
},
success: function (data) {
document.getElementById('Message').innerHTML=data;
},
data: formData,
cache: false,
contentType: false,
processData: false
});
return false;
}
});
});
答案 0 :(得分:0)
这对我有用..
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<script src="http://ajax.aspnetcdn.com/ajax/jquery.validate/1.11.0/jquery.validate.min.js"></script>
<script src="http://ajax.aspnetcdn.com/ajax/jquery.validate/1.11.0/additional-methods.js"></script>
<!-- red color for error message -->
<style type="text/css">
#hardship_form .error {
color: red
}
</style>
<script>
$(document).ready(function() {
$("#relay_form").validate({
rules: {
f_name: {
required: true
}
},
messages: {
f_name: "Please Enter first name"
},
submitHandler: function(form) {
e.preventDefault();
var formData = new FormData($(this).parents('form')[0]);
$.ajax({
url: 'form_relay.php',
type: 'POST',
xhr: function() {
var myXhr = $.ajaxSettings.xhr();
return myXhr;
},
success: function(data) {
document.getElementById('Message').innerHTML = data;
},
data: formData,
cache: false,
contentType: false,
processData: false
});
return false;
}
});
});
</script>
感谢米兰