我创建了一个应用程序,可让用户登录并在谷歌地图上设置标记,标记连接到属于设置它的用户的聊天室。
现在的问题是,无论我如何尝试,我都无法在Chatactivity和MapFragment中获取uid,我不知道问题是什么 这是三项活动:
有人可以帮帮我~~LoginActivity:
unsigned short int
ChatActivity:
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_login);
auth = FirebaseAuth.getInstance();
if (auth.getCurrentUser() != null) {
startActivity(new Intent(LoginActivity.this, MainActivity.class));
finish();
}
//authenticate user
auth.signInWithEmailAndPassword(email, password)
.addOnCompleteListener(LoginActivity.this, new OnCompleteListener<AuthResult>() {
@Override
public void onComplete(@NonNull Task<AuthResult> task) {
// If sign in fails, display a message to the user. If sign in succeeds
// the auth state listener will be notified and logic to handle the
// signed in user can be handled in the listener.
if (!task.isSuccessful()) {
// there was an error
if (password.length() < 6) {
edUserid.setError("密碼太短,請輸入超過6個字元!");
} else {
Toast.makeText(LoginActivity.this, "登入失敗", Toast.LENGTH_LONG).show();
}
} else {
Toast.makeText(getApplicationContext(),"登入成功",Toast.LENGTH_LONG).show();
startActivity(new Intent(LoginActivity.this, MainActivity.class));
finish();
}
}
});
}
}
MapFragment(部分内容):
fab.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
EditText input = (EditText)findViewById(R.id.input);
// Read the input field and push a new instance
// of ChatMessage to the Firebase database
FirebaseDatabase.getInstance()
.getReference(CHAT_PATH)
.push()
.setValue(new ChatMessage(input.getText().toString(),
FirebaseAuth.getInstance()
.getCurrentUser()
.getDisplayName())
);
// Clear the input
input.setText("");
}
});
ListView listOfMessages = (ListView)findViewById(R.id.list_of_messages);
adapter = new FirebaseListAdapter<ChatMessage>(this, ChatMessage.class,
R.layout.message, FirebaseDatabase.getInstance().getReference(CHAT_PATH)) {
@Override
protected void populateView(View v, ChatMessage model, int position) {
// Get references to the views of message.xml
TextView messageText = (TextView)v.findViewById(R.id.message_text);
TextView messageUser = (TextView)v.findViewById(R.id.message_user);
TextView messageTime = (TextView)v.findViewById(R.id.message_time);
// Set their text
messageText.setText(model.getMessageText());
messageUser.setText(model.getMessageUser());
// Format the date before showing it
messageTime.setText(DateFormat.format("dd-MM-yyyy (HH:mm:ss)",
model.getMessageTime()));
}
};
listOfMessages.setAdapter(adapter);
}
答案 0 :(得分:0)
您的数据库结构应如下所示:
通讯录
标记
聊天
使用此结构,您可以从标记获取聊天室ID,并且您也可以使用userId
从标记显示用户信息。
而不是使用push中的userId
,而是使用firebase auth中的uid会更好。
auth.createUserWithEmailAndPassword(email, password)
.addOnCompleteListener(CreateActivity.this, new
OnCompleteListener<AuthResult>() {
public void onComplete( Task<AuthResult> task) {
Toast.makeText(CreateActivity.this, "創建成功,請重新登 入", Toast.LENGTH_SHORT).show();
// If sign in fails, display a message to the user. If sign in succeeds
// the auth state listener will be notified and logic to handle the
// signed in user can be handled in the listener.
if (!task.isSuccessful()) {
Toast.makeText(CreateActivity.this, "認證失敗或帳號已 存在" , Toast.LENGTH_SHORT).show();
} else {
// insert user to database
FirebaseDatabase database = FirebaseDatabase.getInstance();
String currentUid = auth.getCurrentUser().getUid();
DatabaseReference myRef = database.getReference("Contacts/" + currentUid);
ContactInfo contact1 = new ContactInfo(email,id,password);
myRef.setValue(contact1);//將會員資料寫入FIREBASE
startActivity(new Intent(CreateActivity.this, MainActivity.class));
finish();
}
}
});
}