Question

我的表中的数据名为价格，如下所示;

+--------------------------------------+-------+-------+--------+------------+
| ID                                   | E5    | E10   | DIESEL | DATE       |
+--------------------------------------+-------+-------+--------+------------+
| a1978958-a6c4-447b-a90c-3d189da0f831 | 1.289 | 1.269 |  1.059 | 07/22/2017 |
| a1978958-a6c4-447b-a90c-3d189da0f831 | 1.259 | 1.239 |  1.029 | 07/22/2017 |
+--------------------------------------+-------+-------+--------+------------+

我想计算E5，E10，DIESEL的平均值。然后我想在同一个表中合并ID和DATE两列。（列名和顺序将保持不变）

select ID, DATE, avg(E5) as E5, avg(E10) as E10, avg(DIESEL) as DIESEL from prices group by ID, DATE;

然后我插入了以下查询。

select t1.ID, t2.ID, t1.DATE, t2.DATE from prices as t1 inner join prices as t2 on t1.ID = t2.ID and t1.DATE = t2.DATE;

我无法通过两个上述查询来合并两行。结果将是所有行值中的下图。

  +--------------------------------------+-------+-------+--------+------------+
    | ID                                   | E5    | E10   | DIESEL | DATE       |
    +--------------------------------------+-------+-------+--------+------------+
    | a1978958-a6c4-447b-a90c-3d189da0f831 | 1.274 | 1.254 |  1.044 | 07/22/2017 |
    +--------------------------------------+-------+-------+--------+------------+

有什么想法吗？

提前致谢，

Answer 1

这是你正在寻找的东西：将结果保存在临时表中，删除实际值，并将avg值插入到同一个表中？

SELECT ID, avg(E5) as E5, avg(E10) as E10, avg(DIESEL) as DIESEL, DATE INTO #TEMP from prices group by ID, DATE
DELETE FROM prices
INSERT INTO prices SELECT * FROM #TEMP
DROP TABLE #TEMP

Answer 2

你好像要求：

select ID, avg(E5) as E5, avg(E10) as E10, avg(DIESEL) as DIESEL
from prices
group by ID;

这样做你想要的吗？

计算平均值后，在同一个表中合并两行

2 个答案: