Question

我有program.log文件，它的名称为;

2016-12-12 this is a log line 1 [warning]

2016-12-12 this is a log line 2 [warning]

2016-12-12 this is a log line 3 [error]

2016-12-13 this is a log line 4 [error]

2016-12-14 this is a log line 5 [error]

2016-12-14 this is a log line 6 [warning]

我无法在PHP中编写读取此文件并处理其内容的代码并提供日志摘要。最终输出已知，但我无法手动执行此操作。

最终输出看起来像

2016-12-12 warning:2 error: 1

2016-12-13 warning:0 error: 1

2016-12-14 warning:1 error: 1

Answer 1

你不是要求解决方案吗？这仍然适用于使用rejex和一些数组。

<?php
/**
 * Created by PhpStorm.
 * User: Vaibs
 * Date: 22-07-2017
 * Time: 21:52
 */
$logCurrentDate = null;
$logPrevDate = null;
$report = array();


if ($file = fopen("a.log", "r")) {
    $logTypeErrorCount = 0;
    $logTypeWarningCount = 0;
    $isLogError = false;
    while (!feof($file)) {
        $line = fgets($file);
        $a = array();
        preg_match_all("~^\d{4}\-\d{2}-\d{2}+ (this is a log line)+ (\d+)+ \[(.*)\]~", $line, $a);
        $logCurrentDate = substr($a[0][0], 0, 10);
        $logTypeCurrent = $a[3][0];
        $isLogError = ($logTypeCurrent == "error") ? true : false;

        if ($logCurrentDate != $logPrevDate) {
            $report[$logCurrentDate] = array("Warning" => $logTypeWarningCount = $isLogError ? 0 : 1, "Error" => $logTypeError = $logTypeErrorCount = $isLogError ? 1 : 0);

        } else {
            if ($isLogError) {
                $logTypeErrorCount = $logTypeErrorCount + 1;
            } else {
                $logTypeWarningCount = $logTypeWarningCount + 1;
            }
            $report[$logCurrentDate]['Warning'] = $logTypeWarningCount;
            $report[$logCurrentDate]['Error'] = $logTypeErrorCount;
        }
        $logPrevDate = $logCurrentDate;
    }
    //  print_r($report);

    foreach ($report as $x => $x_value) {
        echo $x . '  warning: ' . $x_value['Warning'] . '  error: ' . $x_value['Error'] . PHP_EOL;
    }

    fclose($file);
}

a.log：您的日志文件

2016-12-12 this is a log line 1 [warning]
2016-12-12 this is a log line 2 [warning]
2016-12-12 this is a log line 3 [error]
2016-12-13 this is a log line 4 [error]
2016-12-14 this is a log line 5 [error]
2016-12-14 this is a log line 6 [warning]

读取给定日志文件，处理其内容并提供日志摘要的代码？

1 个答案: