Question

我想创建一个具有如下结构的json对象数组：

{
    "client-mac": "0C:D2:B5:68:73:24",
    "client-dbm": "-82",
    "clientManuf": "unknown"
}

我正在使用以下php代码来获得此结果：

$clientMac = $clients->{'client-mac'};
$clientStrength = $clients->{'snr-info'}->{'last_signal_dbm'};
$clientManuf = $clients->{'client-manuf'};
$jsonObject = array('client-mac' => $clientMac,
                    'client-dbm' => $clientStrength,
                    'clientManuf' => $clientManuf);
$jsonString = json_encode($jsonObject);

问题是我正在关注json字符串：

{"client-mac":{
                 "0":"0C:D2:B5:68:73:24"
              },
 "client-dbm":{
                 "0":"-82"
              },
 "clientManuf":{"0":"Unknown"}
}

为什么我将这些额外的密钥设为“0”？我怎样才能得到我想要的输出？提前谢谢你：）

Answer 1

显然，您的源数据还有一个嵌套级别，其中包含一个键/值对。

您可以使用reset来从中选择第一个值：

array('client-mac' => reset($clientMac),
      'client-dbm' => reset($clientStrength),
      'clientManuf' => reset($clientManuf));

Answer 2

这是因为$clientMac，$clientStrength和$clientManuf是对象，而不是文字字符串。您必须按以下方式更改前三行，

$clientMac = $clients->{'client-mac'}->{'0'};
$clientStrength = $clients->{'snr-info'}->{'last_signal_dbm'}->{'0'};
$clientManuf = $clients->{'client-manuf'}->{'0'};
...

php变量转换为JSON对象

2 个答案: