Question

说我有下面的简单表格：

KeyWordID   KeyWord
----------- ----------
1           Blue
3           Yellow
1           Yellow

如何选择KeyWordID，选择KeyWord为蓝色和黄色的KeyWordID。

E.g。它应该只返回1，因为这是唯一具有两者关键字蓝色和黄色的KeyWordID

我最初认为GROUPBY - 但它并没有按预期工作。

Answer 1

查询

DECLARE @TABLE TABLE (KeyWordID INT, KeyWord VARCHAR(20))

INSERT INTO @TABLE VALUES (1, 'Blue')
INSERT INTO @TABLE VALUES (3, 'Yellow')
INSERT INTO @TABLE VALUES (1, 'Yellow')

SELECT KeyWordID FROM @TABLE
WHERE KeyWord IN ('Blue', 'Yellow') -- Keywords to find
GROUP BY KeyWordID HAVING COUNT(*) = 2 -- Number of keyword to find

结果

KeyWordID
-----------
1

在jzd发表评论后编辑忽略可能的误报：

DECLARE @TABLE TABLE (KeyWordID INT, KeyWord VARCHAR(20))

INSERT INTO @TABLE VALUES (1, 'Blue')
INSERT INTO @TABLE VALUES (1, 'Yellow')
INSERT INTO @TABLE VALUES (3, 'Yellow')
INSERT INTO @TABLE VALUES (3, 'Yellow')

SELECT KeyWordID FROM @TABLE
WHERE KeyWord IN ('Blue', 'Yellow') -- Keywords to find
GROUP BY KeyWordID HAVING COUNT(DISTINCT KeyWord) = 2 -- Number of keyword to find

Answer 2

加入表格本身应该做的诀窍：

SELECT a.KeywordId
FROM MyTable AS a
INNER JOIN MyTable AS b ON a.KeywordId = b.KeywordId
WHERE a.KeyWord = 'Blue'
AND b.KeyWord = 'Yellow'

Answer 3

SELECT KeyWordID FROM <YOUR_TABLE> WHERE KeyWord= 'Blue'
INTERSECT
SELECT KeyWordID FROM <YOUR_TABLE> WHERE KeyWord= 'Yellow'

Answer 4

SELECT KeywordID, COUNT(*) AS BlueAndYellow
FROM myTable
WHERE (Keyword = 'Blue' OR Keyword = 'Yellow')
GROUP BY KeywordID
HAVING COUNT(*) = 2

注意：我没试过这个。但我想这应该有用，并给你一个方法。

如何执行此选择？

4 个答案: