Connection.php第647行中的Laravel QueryException：SQLSTATE [42000]：语法错误或访问冲突

Question

我试图运行以下Query with Query构建器。

table1(date, curr_book_bal)

但我得到了以下错误。 我更改了$products = \DB::table('users') ->join('products','products.auth_id','users.id') ->leftjoin('buys','products.id','buys.product_id') ->select('products.*','users.avatar',DB::raw('COUNT(buys.product_id) as total_sells') ) ->groupBy('products.id') ->where('products.status','=','1') ->take(20) ->paginate(4); Where in products.id could be there in buys table or not.. 。

database.php mysql array from strict = true to false

Answer 1

尝试

$products = \DB::table('users')
->selectRaw('products.*,users.avatar, COUNT(buys.product_id) as total_sells') 
->where('products.status','=','1')
        ->join('products','products.auth_id','=', 'users.id')
        ->leftjoin('buys','products.id','buys.product_id')
        ->groupBy('products.id')                    
        ->take(20)
        ->get();

我不确定paginate是否可以查询构建器。