# Battle Loop
while Battle == 1:
# Taking users action to decide what to do
UserAction = input("Attack, defend, run: ")
# If the User decides to Attack
if UserAction == "Attack" and "attack":
print("Attacking!")
当用户输入“Attack”时,将打印该消息,但是如果用户输入“attack”则会继续请求UserAction而不是打印消息。如何允许IF语句接受两个或更多替代字符串?
答案 0 :(得分:0)
您可以将值转换为小写,然后只进行一次比较。
if UserAction.lower() == "attack":