我正在制作国际象棋程序,我想知道我是否可以通过检查bpawn1 - bpawn8的x位置和y位置并查看x和y位置是否与白色pawn相同来更轻松地完成一个过程所以它杀了典当。
<a href="#" id="status" data-type="select" data-pk="1" data-title="Select status"></a>
<script>
$(function() {
$("#status").editable({
type: "select",
title: 'Select Fruit',
source: [
{text : "Apple", value: "option_1"},
{text : "Orange", value: "option_2"},
{text : "Mango",value: "option_3"},
{text : "Strawberry",value: "option_4"}
],
display: function(value, sourceData) {
if (value) { // value = "option_3" etc.
$(this).html(value);
}
/* OR if you want to access the selected source object ...
var selected = $.fn.editableutils.itemsByValue(value, sourceData);
if (selected.length) {
$(this).html(selected[0].value);
} */
}
});
});
</script>
答案 0 :(得分:0)
这会是你想要的吗?
In [15]: pawn_pos = (1, 3)
In [16]: rook_pos = (4, 6)
In [17]: pawn_pos == rook_pos
Out[17]: False
In [18]: rook_pos = (1, 3)
In [19]: pawn_pos == rook_pos
Out[19]: True
或者,您可以覆盖__eq__
方法。
In [26]: class ChessPiece:
...: def __init__(self, color, x, y):
...: self.x = x
...: self.y = y
...: self.color = color
...: def __eq__(self, other):
...: return (self.x, self.y) == (other.x, other.y)
...:
In [27]: c1 = ChessPiece('black', 1, 3)
In [28]: c2 = ChessPiece('white', 1, 4)
In [29]: c1 == c2
Out[29]: False
In [30]: c2 = ChessPiece('white', 1, 3)
In [31]: c1 == c2
Out[31]: True