Question

我有这段代码：

from os.path import splitext, abspath
from sys import modules

import win32serviceutil
import win32service
import win32event
import win32api

def main():
     # do something

class Service(win32serviceutil.ServiceFramework):
    _svc_name_ = '_unNamed'
    _svc_display_name_ = '_Service Template'
    def __init__(self, *args):
        win32serviceutil.ServiceFramework.__init__(self, *args)
        self.log('init')
        self.stop_event = win32event.CreateEvent(None, 0, 0, None)
    def log(self, msg):
        import servicemanager
        servicemanager.LogInfoMsg(str(msg))
    def sleep(self, sec):
        win32api.Sleep(sec*1000, True)
    def SvcDoRun(self):
        self.ReportServiceStatus(win32service.SERVICE_START_PENDING)
        try:
            self.ReportServiceStatus(win32service.SERVICE_RUNNING)
            self.log('start')
            self.start()
            self.log('wait')
            win32event.WaitForSingleObject(self.stop_event, win32event.INFINITE)
            self.log('done')
        except Exception as x:
            self.log('Exception : %s' % x)
            self.SvcStop()
    def SvcStop(self):
        self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
        self.log('stopping')
        self.stop()
        self.log('stopped')
        win32event.SetEvent(self.stop_event)
        self.ReportServiceStatus(win32service.SERVICE_STOPPED)
    # to be overridden
    def start(self): pass
    # to be overridden
    def stop(self): pass

def instart(cls, name, display_name=None, stay_alive=True):
    ''' Install and  Start (auto) a Service

        cls : the class (derived from Service) that implement the Service
        name : Service name
        display_name : the name displayed in the service manager
        stay_alive : Service will stop on logout if False
    '''
    cls._svc_name_ = name
    cls._svc_display_name_ = display_name or name
    try:
        module_path=modules[cls.__module__].__file__
    except AttributeError:
        # maybe py2exe went by
        from sys import executable
        module_path=executable
    module_file = splitext(abspath(module_path))[0]
    cls._svc_reg_class_ = '%s.%s' % (module_file, cls.__name__)
    if stay_alive: win32api.SetConsoleCtrlHandler(lambda x: True, True)
    try:
        win32serviceutil.InstallService(
            cls._svc_reg_class_,
            cls._svc_name_,
            cls._svc_display_name_,
            startType = win32service.SERVICE_AUTO_START
        )
        print ('Install ok')
        win32serviceutil.StartService(
            cls._svc_name_
        )
        print ('Start ok')
    except Exception as x:
        print (str(x))
    startmain() # to start the main function of the program

Service = Service
instart = instart

class Test(Service):
    def start(self):
        self.runflag=True
        while self.runflag:
            self.sleep(10)
            self.log("I'm alive ...")
    def stop(self):
        self.runflag=False
        self.log("I'm done")

instart(Test, 'aTest', 'Python Service Test')

已成功创建并启动该服务，但具有管理员权限。如果我以普通用户身份执行脚本，则会失败。没有管理员权限，有没有办法做到这一点？我还注意到这个类不仅将脚本作为服务启动，而且还在Services.msc上创建一个。但我不需要它。我可以把我的脚本放在自动运行中（没有管理员烫发就可以。）重要的是我的脚本已经在后台启动了。我能这样做吗？

Python - 在Windows上创建没有管理员权限的服务

0 个答案: