Question

#!/bin/bash
$activity1 = zenity  --list  --text " select the option" --radiolist  --column "Select" --column "you are" FALSE "admin" TRUE "customer" ;


if [ $activity1  = "admin"]; then

 ( zenity --password --username );

else [ $activity1 = "customer" ]; then


( zenity --entry );\

--entry-text ""
fi

我收到错误“语法错误：”然后“意外（期待”fi“）” 任何人都可以给我答案吗？

Answer 1

不应该有其他条件。

你应该有

if [ $activity1  = "admin"]; then
   ( zenity --password --username );
else # no condition
   zenity --entry );\
   --entry-text ""
fi

或使用elif

if [ $activity1  = "admin"]; then
   ( zenity --password --username );
elif [ $activity1 = "customer" ]; then
   ( zenity --entry );\
   --entry-text ""
fi

如何正确使用if else条件来纠正错误

1 个答案: