Question

我必须确定任何容器组是否在具有任何结果的多个组中进行测试。

我觉得我需要一个简单的循环，但不能在我的脑海中构建它。有一组4个表通过测试连接容器中的所有点，然后到结果。

表con_group1包含 container_groups 。表containers2包含 container_group_ids 和各个 container_ids 和 test_group ID。表test_groups3包含 test_group_ids 和 test_ids ，表tests4包含 test_ids 和 result_id 。 Table 5包含结果。

我需要确定哪些容器都有测试结果。无论结果如何，只要容器中包含的每个测试都有结果。

------------------------------------
|  Container  |   Test   |  Result |
------------------------------------
|    8        |    69    |         |
|    9        |    87    |    8    |
|    8        |    45    |         |
|    6        |    58    |         |
|    9        |    95    |    5    |
------------------------------------

期望的结果：

------------------------- 
| Container Group |           |
-------------------------
|        2     |    done   |
|        1     |    open   |
|        3     |    open   |
-------------------------

{CREATE TABLE CONTAINERS2
(CON_GROUP  NUMBER(10),
CONTAINER  NUMBER(10));

CREATE TABLE CON_GROUP1
(CON_GROUP  NUMBER(10));
CREATE TABLE TESTS4
(RESULT_ID  NUMBER(10),
  TEST       NUMBER(10));

CREATE TABLE TEST_GROUPS3
(CONTAINER  NUMBER(10),
TEST       NUMBER(10));

INSERT INTO CONTAINERS2(CON_GROUP, CONTAINER) VALUES (1, 8);
INSERT INTO CONTAINERS2(CON_GROUP, CONTAINER) VALUES (3, 6);
INSERT INTO CONTAINERS2(CON_GROUP, CONTAINER) VALUES (2, 9);
INSERT INTO CON_GROUP1(CON_GROUP) VALUES(1);
INSERT INTO CON_GROUP1(CON_GROUP) VALUES(2);
INSERT INTO CON_GROUP1(CON_GROUP) VALUES(3);

 INSERT INTO TESTS4(RESULT_ID, TEST) VALUES (8, 87);
 INSERT INTO TESTS4 (RESULT_ID, TEST) VALUES (NULL, 45);
 INSERT INTO TESTS4 (RESULT_ID, TEST) VALUES(NULL, 58);
 INSERT INTO TESTS4  (RESULT_ID, TEST) VALUES (NULL, 69);
 INSERT INTO TESTS4 (RESULT_ID, TEST) VALUES(5, 95);

 INSERT INTO TEST_GROUPS3(CONTAINER, TEST) VALUES(8, 45);
 INSERT INTO TEST_GROUPS3 (CONTAINER, TEST) VALUES(9, 87);
 INSERT INTO TEST_GROUPS3 (CONTAINER, TEST) VALUES(6, 58);
 INSERT INTO TEST_GROUPS3(CONTAINER, TEST) VALUES (8, 69);
 INSERT INTO TEST_GROUPS3(CONTAINER, TEST) VALUES (9, 95);}

Answer 1

一系列LEFT JOIN和GROUP BY可以完成这项工作：

SELECT cg.con_group,
       max( CASE WHEN result_id IS NULL
                 THEN 'Open' ELSE 'Closed'
            END ) As Result
FROM con_group1 cg
LEFT JOIN CONTAINERS2 co ON co.con_group = cg.con_group 
LEFT JOIN TEST_GROUPS3 tg ON tg.container = co.container
LEFT JOIN TESTS4 t4 ON t4.TEST = tg.TEST
GROUP BY cg.con_group

演示：SQLFiddle

| con_group | result |
|-----------|--------|
|         1 |   Open |
|         3 |   Open |
|         2 | Closed |

...需要确定哪些容器组符合条件，而不是容器.. 容器必须有资格获得容器组资格..

如果我理解这个要求，你需要：

SELECT cg.con_group,
       co.CONTAINER,
       max( CASE WHEN result_id IS NULL
                 THEN 'Open' ELSE 'Closed'
            END ) As Result
FROM con_group1 cg
LEFT JOIN CONTAINERS2 co ON co.con_group = cg.con_group 
LEFT JOIN TEST_GROUPS3 tg ON tg.container = co.container
LEFT JOIN TESTS4 t4 ON t4.TEST = tg.TEST
GROUP BY cg.con_group,
         co.CONTAINER

演示：SQLFiddle

| con_group | container | result |
|-----------|-----------|--------|
|         1 |         8 |   Open |
|         2 |         9 | Closed |
|         3 |         6 |   Open |

Answer 2

您需要计算每个容器的测试次数和每个容器的结果测试次数，并比较两个结果集。此解决方案使用子查询来获取两个计数和一个外部联接（因为可能一组测试根本没有结果）：

with tests as 
    ( select tg.container
             , count(tg.test) as tst_cnt
      from test_groups3 tg
      group by tg.container )
  , results as  
    ( select tg.container
             , count(tr.test) as tst_cnt
      from test_groups3 tg
           join tests4 tr
               on tr.test = tg.test 
      group by tg.container )
select tests,container
       , case when tests.tst_cnt = results.tst_cnt
             then 'done'
         else 'open' 
         end as status
from tests
     left join results
     on tests.constainer = results.container
/

在具有结果的组内查找测试 - Oracle 12

2 个答案: